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kipiarov [429]
3 years ago
11

Physics! Someone help me! Its due today please!

Mathematics
1 answer:
icang [17]3 years ago
6 0

Step-by-step explanation:

We have,

Mass of ball is 9 kg

Initial speed, u = 5 m/s

Final speed, v = -2 m/s (negative as it bounces off)

(a) The change in velocity of the bowling ball is :

\Delta v=v-u\\\\\Delta v=-2-5\\\\\Delta v=-7\ m/s

(b) Change of momentum of the ball is :

p=m\Delta v\\\\p=90\times (-7)\\\\p=-630\ kg-m/s

|p| = 630 kg-m/s

(c) Impulse momentum theorem states that the change in momentum of the ball is equal to the impulse exerted on the ball. So, impulse is 630 kg-m/s.

(d) Impulse is also given by :

J=F\times t\\\\F=\dfrac{J}{t}\\\\F=\dfrac{630}{0.3}\\\\F=2100\ N

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Answer:

Use the quadratic formula

=

−

±

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−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

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5

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+

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a={\color{#c92786}{5}}

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=

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=

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(

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±

(

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1

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2

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4

⋅

5

⋅

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