Question

Physics! Someone help me! Its due today please!

Answer 1

Step-by-step explanation:

We have,

Mass of ball is 9 kg

Initial speed, u = 5 m/s

Final speed, v = -2 m/s (negative as it bounces off)

(a) The change in velocity of the bowling ball is :

$\Delta v=v-u\\\\\Delta v=-2-5\\\\\Delta v=-7\ m/s$

(b) Change of momentum of the ball is :

$p=m\Delta v\\\\p=90\times (-7)\\\\p=-630\ kg-m/s$

|p| = 630 kg-m/s

(c) Impulse momentum theorem states that the change in momentum of the ball is equal to the impulse exerted on the ball. So, impulse is 630 kg-m/s.

(d) Impulse is also given by :

$J=F\times t\\\\F=\dfrac{J}{t}\\\\F=\dfrac{630}{0.3}\\\\F=2100\ N$