Step-by-step explanation:
We have,
Mass of ball is 9 kg
Initial speed, u = 5 m/s
Final speed, v = -2 m/s (negative as it bounces off)
(a) The change in velocity of the bowling ball is :
(b) Change of momentum of the ball is :
|p| = 630 kg-m/s
(c) Impulse momentum theorem states that the change in momentum of the ball is equal to the impulse exerted on the ball. So, impulse is 630 kg-m/s.
(d) Impulse is also given by :
ST = 7.2
RT = 4.04
m∠S = 34°
Solution:
Given ΔRST is a right triangle.
RS = 6, ∠T = 56°
1.206 × 6 = ST
7.236 = ST
ST = 7.2
0.674 × 6 = RT
4.044 = RT
RT = 4.04
To find the measure of angle S.
Sum of the interior angles of the triangle = 180°
m∠R + m∠S + m∠T = 180°
90° + m∠S + 56° = 180°
m∠S + 146° = 180°
m∠S = 180° – 146°
m∠S = 34°
Answer:
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