Answer: 286 minutes
Step-by-step explanation:
x : # of months that has gone by
0.24x : cost of the 24 cent plan after "x" minutes
39.95 + 0.10x : cost of the 10 cent plan after "x" minutes
1. 39.95 + 0.10x > 0.24x
2. 39.95 > 0.24x - 0.10x
3. 39.95 > 0.14x
4. 285.36 > x
x must be AT LEAST 286 minutes for plan #2 (39.95 + 0.10x) to be a better deal
Capacity of the hard drive = 160 GB.
Used space = 122 GB.
Free space = 160 - 122 = 38 GB.
So, the size of the home video collection should be less than or equal to 38 GB.
If u is the amount of space used, then, u ≤ 38
If a is the amount of space available, then a = 38 - u.
Answer:
Step-by-step explanation:
(96 minutes)/(32 sculptures) = (96/32 minutes)/sculpture = (3 minutes)/sculpture
It takes 3 minutes to make one sculpture.
(160 balloons)/(32 sculptures) = (160/32 balloons)/sculpture = (5 balloons)/sculpture
It takes 5 balloons to make one sculpture.
(160 balloons)/(96 minutes) ≈ 1.7 balloons used per minute.
Answer:
5/ 19 ≈ 0.26 = 26%
Step-by-step explanation:
given: student is female. there is a 100% chance that the student is female
probability we want = (favorable outcomes) / (total outcomes)
total outcomes = 19 because there are 19 female students and the student must be female
favorable outcomes = 19 - 14 = 5 females who do not have an A in the class
probability = 5/ 19 ≈ 0.26 = 26%
Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
