C
6x^2-13X-5=0
(3X+1)(2X-5)
3x-1=0
X=1/3. 2x-5=0. X= 5/2
Answer:
4/15 is your answer my friend
Step-by-step explanation:
Answer:
The correct option is B.
Step-by-step explanation:
Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .
Draw a diagonal AC.
In triangle BCA and DAC,
AC\cong ACAC≅AC (Reflexive Property of Equality)
\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)
\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)
The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.
By ASA postulate,
\triangle BCA\cong \triangle DAC△BCA≅△DAC
Therefore option B is correct
Answer:
8/5 < x< 12/5
Step-by-step explanation:
(2 - x)^2 < 4/25
Take the square root of each side
sqrt((2 - x)^2) <±sqrt( 4/25)
Make two equations
2-x < 2/5 2-x > -2/5
Subtract 2 from each side
2-x-2 < 2/5 -2 2-x-2 > -2/5-2
-x < 2/5 - 10/5 -x > -2/5 - 10/5
-x < -8/5 -x > -12/5
Multiply by -1, remembering to flip the inequality
x> 8/5 x < 12/5
8/5 < x< 12/5
Answer:
12/13
Step-by-step explanation:
The length of the segment from the origin to the terminal point is ...
r = √((-5)² +12²) = √169 = 13
The sine of the angle is the ratio of the y-coordinate to this distance
sin(θ) = y/r = 12/13
_____
Additional comment
The other trig functions are ...
cos(θ) = x/r = -5/13
tan(θ) = y/x = -12/5
This is a 2nd-quadrant angle, where the sine is positive, but the cosine and tangent are negative.
