Which equation can be used to determine the distance between the origin and (–2, –4)?

Mathematics

2 answers:

Paladinen [302]3 years ago

8 0

Answer:

2√5

Step-by-step explanation:

Were there answer choices from which to choose? If so, please share them next time.

The Pythagorean Theorem would suit very well in finding this distance.

The horizontal distance between the two points is 2 (I'm neglecting the - sign), and the vertical distance is 4. Thus, the distance between the two points is

d = √ [ 2^2 + 4^2 ] = √ [20] = √4*√5 = 2√5

Andreyy893 years ago

3 0

-2+(-4) i think :)))

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Let A be the set of all lines in the plane. Define a relation R on A as follows. For every l1 and l2 in A, l1 R l2 ⇔ l1 is paral

Lyrx [107]

Answer:

Hence, the relation R is a reflexive, symmetric and transitive relation.

Given :

A be the set of all lines in the plane and R is a relation on set A.

$R=\{l_1,l_2\in A|l_1 \;\text{is parallel to}\; l_2\}$

To find :

Which type of relation R on set A.

Explanation :

A relation R on a set A is called reflexive relation if every $a\in A$ then $(a,a)\in R$ .

So, the relation R is a reflexive relation because a line always parallels to itself.

A relation R on a set A is called Symmetric relation if $(a,b)\in R$ then $(b,a)\in R$ for all $a,b\in A$ .

So, the relation R is a symmetric relation because if a line $l_1$ is parallel to the line $l_2$ the always the line $l_2$ is parallel to the line $l_1$ .

A relation R on a set A is called transitive relation if $(a,b)\in R$ and $(b,c)\in R$ then $(a,c)\in R$ for all $a,b,c\in A$ .

So, the relation R is a transitive relation because if a line $l_1$ s parallel to the line $l_2$ and the line $l_2$ is parallel to the line $l_3$ then the always line $l_1$ is parallel to the line $l_3$ .