Which equation can be used to determine the distance between the origin and (–2, –4)?

Mathematics

2 answers:

Paladinen [302]2 years ago

8 0

Answer:

2√5

Step-by-step explanation:

Were there answer choices from which to choose? If so, please share them next time.

The Pythagorean Theorem would suit very well in finding this distance.

The horizontal distance between the two points is 2 (I'm neglecting the - sign), and the vertical distance is 4. Thus, the distance between the two points is

d = √ [ 2^2 + 4^2 ] = √ [20] = √4*√5 = 2√5

Andreyy892 years ago

3 0

-2+(-4) i think :)))

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What is the difference?

Crazy boy [7]

Answer:

<h2>D. $\frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\$ or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>

Step-by-step explanation:

Given the expression $\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }$ , the dfference is expressed as follows;

Step1: First we need to factorize the denominator of each function.

$\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }\\= \frac{x}{x^{2}-5x+3x-15 } - \frac{4}{x^{2} + 7x-5x - 35 }\\= \frac{x}{x(x-5)+3(x-5) } - \frac{4}{x( x+ 7)x-5(x +7) }\\= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\\\$

Step 2: We will find the LCM of the resulting expression

$= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\= \frac{x(x+7)-4(x+3)}{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\$