All categories

3 years ago

Does this graph represents a function? why or why not?

Mathematics

1 answer:

ankoles [38]3 years ago

3 0

Answer:

Yes, it passes the vertical line test

Step-by-step explanation:

This graph has a one to one correspondence and will pass the vertical line test, there fore it is a function

You might be interested in

A winch is being used to pull a 3500-lb vehicle 30'. How much work is performed?

AlekseyPX

Answer:

105,000 foot-pounds.

Step-by-step explanation:

Work done = 3500 * 30 foot pounds

3 0

3 years ago

If θ is in standard position and -180° < θ <-90°, then θ terminates in Quadrant _____.

Murljashka [212]

The answer is: A
Cause I had this test before and I aced it ;)

6 0

2 years ago

15 POINTS‼️‼️‼️<br><br> Part B: Solve for x. Show your work.

Musya8 [376]

Answer:

Step-by-step explanation:

A straight line adds up to 180 degrees, therefore 3x+6x = 180

9x = 180

x = 20

7 0

2 years ago

Question 1 of 25

aleksklad [387]

SAS i believe :) sorry if im wrong!

8 0

2 years ago

I’m stuck can some one help me

abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

We have $x_1=2, y_1=-7, x_2=-10,y_2=8$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )$

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

We have $x_1=2, y_1=-10, x_2=3,y_2=10$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )$

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

$x^2-3x-28$

We will break the middle term and find factors

$x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)$

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

$x^2+6x+8$

We will break the middle term and find factors

$x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)$

So, the factors are (x+4)(x+2)

Option A is correct.

7 0

2 years ago