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Zanzabum
3 years ago
8

State 4 components of the environment​

Geography
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

lithosphere, hydrosphere, atmosphere and biosphere

Explanation:

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Name the natural vegetation found in the Western slopes of the Western ghats. give two examples of trees.
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Tropical evergreen forests are found on the western slopes of the Western Ghats. (ii) The Southern Mountain forests are found in the Nilgiris. (iii) Dry scrub and vegetation are found in Western Rajasthan.
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Explain how large-scale agriculture leads to increased atmospheric CO2.
allochka39001 [22]

Answer:

Large scale agriculture will definitely lead to increased CO2.

Explanation:

This is due to the fact that plants give out oxygen and take in CO2 which is released by animals and man , so due to the large scale agriculture, the excess oxygen released by plants purifies the air of poisonous gases like carbon monoxide and leaving it with carbon dioxide- CO2.

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3 years ago
HELP!!! I'LL GIVE 95 POINTS!! In two to three paragraphs, develop an argument that explains the significance of the end of the C
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I'm not writing 2-3 paragraphs for YOUR work

Explanation:

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Which is the best explanation for how earthquakes cause tsunamis? a. Earthquakes shift the seafloor upward or downward, causing
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3 years ago
ACT scores of a sample of UTC students are shown below. Student ACT Score A 22 B 28 C 20 D 21 E 28 F 23 G 26 a. Compute the mean
alisha [4.7K]

Solution :

a). Let  x denotes ACT scores.

ACT scores = $\{ 22,28,20,21,28,23,26 \} ; n = 7$

Mean, $(\overline x)=\frac{\sum x_i}{n}$

                $=\frac{168}{7}=24$

Sample variance, $S^2=\frac{1}{n-1}\left(\sum x_i^2-n\overline x^2 \right)$

                                  $=\frac{1}{6}(4098-7 \times 24^2)$

                                   $=\frac{66}{6}$

                                   = 11

b). To test whether or not variance of ACT scores of population (say $\sigma^2$) of the UTC students is significantly more than 8.

Consider the hypothesis :

$H_0: \sigma^2 \leq8$  vs $H_a: \sigma^2 >8$

It is a right tailed test and α = 0.05

We have

$x^2_{n-1} = \frac{(n-1)s^2}{\sigma^2}$

So test statics is

$x^2_7=\frac{(7-1)11}{8}$

   $=\frac{6 \times 11}{8}$

   = 8.25

Since our \text{test statistics is less than the critical value }and it falls in a acceptation region, hence we fail to reject $H_0$ and conclude that variance is not greater than 8 significantly.

8 0
3 years ago
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