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noname [10]
3 years ago
13

Use ∆ABC to find the value of cos A.

Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0
Using the catchphrase SohCahToa, we can determine that the cosine ratio is equal to the length of the side adjacent to the angle over the length of the hypotenuse of the right triangle.

To find the cos∠A, we will look for side lengths BC and AB.

cosA = \frac {9}{41}

Since \frac {9}{41} is already in it's simplest form, we can conclude that the cosine of ∠A is \frac {9}{41}.

Hope this helps! :^)

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3 years ago
12 less than or equal to 7 + n
SOVA2 [1]
Need more to the question
3 0
4 years ago
Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

4 0
3 years ago
What is the 24,40,56,72 pattern?
zimovet [89]

This is a arithmetic sequence, so all we need to do is subtract the numbers and find the common difference.

40 - 24 = 16

56 - 40 = 16

72 - 56 = 16

Therefore, the common difference is 16.

Best of Luck!

5 0
3 years ago
Read 2 more answers
3. Which of the following side lengths could form a triangle? Check all that apply.​
mario62 [17]

Answer:

2, 6

Step-by-step explanation:

i dont know

6 0
3 years ago
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