Question

The length of a rectangle is 1m more than twice its width, and the area of the rectangle is 66m2. Find the dimensions of the rectangle.

Answer 1

A = LW
A = 66
L = 2W + 1

66 = W(2W + 1)
66 = 2W^2 + W
2W^2 + W - 66 = 0
(2W - 11)(W + 6) = 0

2W - 11 = 0
2W = 11
W = 11/2
W = 5.5

W + 6 = 0
W = -6 (this is an extraneous solution...it will not work)

L = 2W + 1 = 2(5.5) + 1 = 12

so ur dimensions are : Length = 12m and width = 5.5m