Answer:
Step-by-step explanation:
To solve this problem you need the function
h(t) = -16t2 + v0t + h0
where t = time
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
0 = -16 t2 + 256
And we can solve for t
If we rearrange the terms we see that this is a difference of 2 squares
0 = 256 - 16t2
0 = (16-4t)(16+4t)
Setting each factor = 0
16-4t=0 16+4t=4
t = 4 t = -4
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.
(24)(20)2= 960 the answer to the question
Answer: 11.25 secs
Step-by-step explanation:
So in this sense the rockets origin or the ground is modeled at h=0 so the time required if used on a table shows that h=0 between the values of 11 and 12. So if you plug and chug decimal values between these two values you get exactly 0 at t=11.25 so it takes approximately 11.25 seconds for the rocket to return to the ground
To solve this, you just divide 20 divided by 7.
20/7 = <span>2.85714285714
If you are trying to round to the nearest tenth, the next decimal place (hundredths) is a 5, so you must round 2.8 up one more digit.
Your final answer is that</span> 20/7 = 2.9 when rounded to the nearest tenth.
