<span><span>Frist write down the decimal divided by 1 then m</span><span>ultiply both top and bottom by 10 for every number after the decimal point. lastly s</span><span>Simplify (or reduce) the fraction</span></span>
Answer:
![\fbox{ \sf{Perimeter \: of \: a \: rectangle = 10x - 2}}](https://tex.z-dn.net/?f=%20%5Cfbox%7B%20%5Csf%7BPerimeter%20%5C%3A%20of%20%5C%3A%20a%20%5C%3A%20rectangle%20%3D%2010x%20-%202%7D%7D)
Step-by-step explanation:
![\star{ \sf{ \: \: Length \: of \: a \: rectangle ( l ) = (2x - 5) }}](https://tex.z-dn.net/?f=%20%5Cstar%7B%20%5Csf%7B%20%5C%3A%20%20%5C%3A%20Length%20%5C%3A%20of%20%5C%3A%20a%20%5C%3A%20rectangle%20%28%20l%20%29%20%20%3D%20%282x%20-%205%29%20%7D%7D)
![\star{ \sf{ \: Width \: of \: a \: rectangle ( w ) = (3x + 4)}}](https://tex.z-dn.net/?f=%20%5Cstar%7B%20%5Csf%7B%20%5C%3A%20Width%20%5C%3A%20of%20%5C%3A%20%20a%20%5C%3A%20rectangle%20%28%20w%20%29%20%3D%20%283x%20%2B%204%29%7D%7D)
![\star{ \sf{ \: \: Perimeter \: of \: a \: rectangle = ?}}](https://tex.z-dn.net/?f=%20%5Cstar%7B%20%5Csf%7B%20%5C%3A%20%20%5C%3A%20Perimeter%20%5C%3A%20of%20%5C%3A%20a%20%5C%3A%20rectangle%20%3D%20%20%3F%7D%7D)
![\boxed{ \bold{ \sf{Perimeter \: of \: a \: rectangle = 2(l + w)}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cbold%7B%20%20%5Csf%7BPerimeter%20%5C%3A%20of%20%5C%3A%20a%20%5C%3A%20rectangle%20%3D%202%28l%20%2B%20w%29%7D%7D%7D)
![\hookrightarrow{ \sf{Perimeter \: of \: a \: rectangle = 2(2x - 5 + 3x + 4)}}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%7B%20%5Csf%7BPerimeter%20%5C%3A%20of%20%5C%3A%20a%20%5C%3A%20rectangle%20%3D%202%282x%20-%205%20%2B%203x%20%2B%204%29%7D%7D)
![\text{Step \: 1 : \: Collect \: like \: term}](https://tex.z-dn.net/?f=%20%5Ctext%7BStep%20%5C%3A%201%20%3A%20%5C%3A%20Collect%20%5C%3A%20like%20%5C%3A%20term%7D)
![\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base}](https://tex.z-dn.net/?f=%20%20%5Ctext%7BLike%20%5C%3A%20terms%20%5C%3A%20are%20%5C%3A%20those%20%5C%3A%20which%20%5C%3A%20have%20%5C%3A%20the%20%5C%3A%20same%20%5C%3A%20base%7D)
![\hookrightarrow{ \sf{2(2x + 3x - 5 + 4)}}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%7B%20%5Csf%7B2%282x%20%20%2B%203x%20-%205%20%2B%204%29%7D%7D)
![\hookrightarrow{ \sf{2(5x - 5 + 4)}}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%7B%20%5Csf%7B2%285x%20-%205%20%2B%204%29%7D%7D)
![\text{Step \: 2 \: : \: Subtract \: 4 \: from \: 5}](https://tex.z-dn.net/?f=%20%5Ctext%7BStep%20%5C%3A%202%20%20%5C%3A%20%3A%20%20%5C%3A%20Subtract%20%5C%3A%204%20%5C%3A%20from%20%5C%3A%205%7D)
![\text{Remember !\: : the \: negative \: and \: positive \: integers \: are \: always \: subtracted \: but \: posses \: the \: sign \: of \: the \: bigger \: integer}](https://tex.z-dn.net/?f=%20%5Ctext%7BRemember%20%21%5C%3A%20%20%3A%20the%20%5C%3A%20negative%20%5C%3A%20and%20%5C%3A%20positive%20%5C%3A%20integers%20%5C%3A%20are%20%5C%3A%20always%20%5C%3A%20subtracted%20%5C%3A%20but%20%5C%3A%20posses%20%5C%3A%20the%20%5C%3A%20sign%20%5C%3A%20of%20%5C%3A%20the%20%5C%3A%20bigger%20%5C%3A%20integer%7D)
![\hookrightarrow{ \sf{2(5x - 1)}}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%7B%20%5Csf%7B2%285x%20-%201%29%7D%7D)
![\text{Step \: 3 \: : \: Distribute \: 2 \: through \: the \: parentheses}](https://tex.z-dn.net/?f=%20%5Ctext%7BStep%20%5C%3A%203%20%5C%3A%20%20%3A%20%20%5C%3A%20Distribute%20%5C%3A%202%20%5C%3A%20through%20%5C%3A%20the%20%5C%3A%20parentheses%7D)
![\hookrightarrow{ \sf{2 \times 5x - 2 \times 1}}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%7B%20%5Csf%7B2%20%5Ctimes%205x%20-%202%20%5Ctimes%201%7D%7D)
![\hookrightarrow{ \sf{10x - 2}}](https://tex.z-dn.net/?f=%20%5Chookrightarrow%7B%20%5Csf%7B10x%20-%202%7D%7D)
![\sf{∴ \: The \: perimeter \: of \: a \: rectangle = 10x - 2}](https://tex.z-dn.net/?f=%20%5Csf%7B%E2%88%B4%20%5C%3A%20The%20%5C%3A%20perimeter%20%5C%3A%20of%20%5C%3A%20a%20%5C%3A%20rectangle%20%3D%2010x%20-%202%7D)
![\text{Hope \: I \: helped !}](https://tex.z-dn.net/?f=%20%5Ctext%7BHope%20%5C%3A%20I%20%5C%3A%20helped%20%21%7D)
![\text{Best \: regards ! }](https://tex.z-dn.net/?f=%20%5Ctext%7BBest%20%5C%3A%20regards%20%21%20%7D)
~![\text{TheAnimeGirl}](https://tex.z-dn.net/?f=%20%5Ctext%7BTheAnimeGirl%7D)
Answer:
The parent absolute value function is translated 2 units TO THE RIGHT and 4 units DOWN
Step-by-step explanation:
It’s 14
3(4) + 2
12+2 = 14
You have to substitute x by 4
Answer:
Correct answer: x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
Step-by-step explanation:
Given:
3 x⁴ + 14 x² - 5 = 0 biquadratic equation
this equation is solved by a shift x² = t and get:
3 t² + 14 t - 5 = 0
t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6
t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6
t₁ = -5 or t₂ = 1 / 3
the solution t₁ = -5 is not accepted because it cannot be x² = -5
we accepted t₂ = 1 / 3
x² = 1 / 3 ⇒
x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
God is with you!!!