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3 years ago

Divide (10m^8+4m^6+10m^5) / 2m^2

Mathematics

2 answers:

anastassius [24]3 years ago

3 0

Answer:

last option at the bottom

Step-by-step explanation:

(see attached)

gulaghasi [49]3 years ago

3 0

Answer:

5m^6 + 2m^4 + 5m^3

hope this works!!!!

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Isolate the variable x. - 5x < 10

Neporo4naja [7]

Answer:

x > - 2

x ∈ ( - 2 ; + oo)

Step-by-step explanation:

- 5x < 10 | *(-)

5x > - 10 | : 2

x > - 2

x ∈ ( - 2 ; + oo)

8 0

3 years ago

0.16(a-4)=0.3(2a+4)<br>Solve the Equation

Black_prince [1.1K]

The answer is a= -4.181818

5 0

3 years ago

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0

2 years ago

SOMEONE PLEASE ANSWER ASAP THIS FOR BRAINLIEST!!!!

kirill115 [55]

wow the answer is not listed on option

3 0

3 years ago

What plus what equals 55

Dafna1 [17]

1 + 54 = 55
2 + 53 = 55
3 + 52 = 55
4 + 51 = 55
5 + 50 = 55
6 + 49 = 55
7 + 48 = 55
8 + 47 = 55
9 + 46 = 55
10 + 45 = 55
and so on...

I hope that helps. :)

4 0

3 years ago

Read 2 more answers