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Jet001 [13]
3 years ago
10

Help would be greatly appreciated :)

Mathematics
1 answer:
Anton [14]3 years ago
7 0
The bottle of 100 would be lowest. $8.13 ÷ 100 lozenges = $0.08 per lozenge

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Talayah bought two journals. The second journal cost $12 more than 4/5 the price of the first journal. If she spent $30 on both,
sertanlavr [38]
The second journal is $18
7 0
3 years ago
Which point would map onto itself after a reflection across the line y = –x?
Rudiy27

Answer:

+x=-y

Step-by-step explanation:

5 0
3 years ago
PLESEEE HELP I WILL GIVE THE BRAINLIEST TO THE BEST ANWSERS
miss Akunina [59]
The answer to the first question is D.)

The 6 in front of the parentheses modifies both 'x' and 3

The answer to the second question is D.)

When you plug 4 into the equation, you get 14

3(4) + 2 = 14
12 + 2 = 14
14=14

Hope this helps!
6 0
3 years ago
Read 2 more answers
Need a little help? :L
NISA [10]
Answers: -3 and 1

f(-3) = -2(-3) = 6
g(-3) = (-3)^2 - 3 = 9 - 3 = 6

f(1) = -2(1) = -2
g(1) = (1)^2 - 3 = 1 - 3 = -2


3 0
4 years ago
A sample of 900 computer chips revealed that 61% of the chips fail in the first 1000 hours of their use. The company's promotion
Vlad [161]

Answer:

The p-value of the test is 0.0301 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

The company's promotional literature claimed that under 64% fail in the first 1000 hours of their use.

At the null hypothesis, we test if the proportion is of at least 64%, that is:

H_0: p \geq 0.64

At the alternative hypothesis, we test if the proportion is of less than 64%, that is:

H_1: p < 0.64

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

64% is tested at the null hypothesis:

This means that \mu = 0.64, \sigma = \sqrt{0.64*0.36}

A sample of 900 computer chips revealed that 61% of the chips fail in the first 1000 hours of their use.

This means that n = 900, X = 0.61

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.61 - 0.64}{\frac{\sqrt{0.64*0.36}}{\sqrt{900}}}

z = -1.88

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.61, which is the p-value of z = -1.88.

Looking at the z-table, z = -1.88 has a p-value of 0.0301.

The p-value of the test is 0.0301 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the company's claim.

8 0
3 years ago
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