1/2(2+a)=3a+4/3
first, you use the distributive property<span>
</span>then your problem changes to...
1 + 1/2a = 3a + 4/3
then you subtract 1/2a with 3a
1 = 2 1/2a +4/3
<span>
now you subtract 1 with 4/3
</span>
-1/3 = 2 1/2a
now you divide -1/3 with 2 1/2a
-2/15 = a
A = -2/15 is your answer. Hope this helps :)
4*25=100
The glacier was 100 feet shorter than it was originally by the end of the 25 day period.
Hope this helps :)
Answer:
13 miles
Step-by-step explanation:
27.50- 1.50(fee)=26.00 26/2(2$per mile)=13 miles
Answer:
μ = 235.38
σ = 234.54
Step-by-step explanation:
Assuming the table is as follows:
![\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DSavings%26Frequency%5C%5C%5C%240-%5C%24199%26339%5C%5C%5C%24200-%5C%24399%2686%5C%5C%5C%24400-%5C%24599%2655%5C%5C%5C%24600-%5C%24799%2618%5C%5C%5C%24800-%5C%24999%2611%5C%5C%5C%241000-%5C%241199%268%5C%5C%5C%241200-%5C%241399%263%5Cend%7Barray%7D%5Cright%5D)
This is an example of grouped data, where a range of values is given rather than a single data point. First, find the total frequency.
n = 339 + 86 + 55 + 18 + 11 + 8 + 3
n = 520
The mean is the expected value using the midpoints of each range.
μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520
μ = 122400 / 520
μ = 235.38
The variance is:
σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)
σ² = 55009.7
The standard deviation is:
σ = 234.54
Answer: 21 . . . . . .
Credit to the person below-