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malfutka [58]
3 years ago
6

Find the sum of all integers between 550 and 850 which are divisible by 11.

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

19008

Step-by-step explanation:

550 is equal to 11 multiplied by 50.

1. Solve for multiples of 11 between 550 and 850

11 · 51 = 561

11 · 52 = 572

11 · 53 = 583

11 · 54 = 594

11 · 55 = 605

11 · 56 = 616

11 · 57 = 627

11 · 58 = 638

11 · 59 = 649

11 · 60 = 660

11 · 61 = 671

11 · 62 = 682

11 · 63 = 693

11 · 64 = 704

11 · 65 = 715

11 · 66 = 726

11 · 67 = 737

11 · 68 = 748

11 · 69 = 759

11 · 70 = 770

11 · 71 = 781

11 · 72 = 792

11 · 73 = 803

11 · 74 = 814

11 · 75 = 825

11 · 76 = 836

11 · 77 = 847

2. Add the products together

= 19008

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If f(x)=5x-2 and g(x)=2x+1, find (f+g)(x)<br> A.7x-3 <br> B.3x-1 <br> C.7x-1 <br> D.4x-3
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Answer:

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Step-by-step explanation:

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3 years ago
Is (-3,2)(−3,2)left parenthesis, minus, 3, comma, 2, right parenthesis a solution of -4x -10y &lt; -9−4x−10y&lt;−9minus, 4, x, m
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Answer:

The answer to your question is The point (-3, 2) is not a solution

Step-by-step explanation:

Inequality

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Process

1.- To solve this problem, just substitute the point in the inequality and simplify

a) Substitution

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b) Simplification

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c) Result

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