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4 years ago

___ tens 15 ones=4 tens 5 ones

Mathematics

1 answer:

saw5 [17]4 years ago

3 0

Answer:

3 tens

Step-by-step explanation:

4 tens and 5 ones is 45

so 45 minus 15 is 30

so 3 tens

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What is the slope-intercept equation of the line below? 61 -5

Lemur [1.5K]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The Correct option is ~ B

$\boxed{ \boxed{y = 2x - 3}}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's find the slope (m) using points (2 , 1) and (0 , -3)

$\mathrm{ \dfrac{y2 - y1}{x2 - x1} }$

$\dfrac{1 - ( - 3)}{2 - 0}$

$\dfrac{4}{2}$

hence, slope = 2

now, by Observing the given graph we can infer that the given line cuts the y - axis at point (0 , -3), so value of y - intercept (c) = - 3

[ y - coordinate of a point when x - coordinate is equal to 0 is the value of y - intercept of a line ]

And, we know the general equation of line in slope - intercept form is ~

$\boxed{y = mx + c}$

now, let's plug the value of slope (m) and y - intercept (c) in the general equation to find the equation of line in slope intercept form ~

$y = 2x - 3$

7 0

3 years ago

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

4 years ago

what key feature(s) can be easily identified from factored form? explain how each key feature is related to the roller coaster.

Ulleksa [173]

Answer:

Step-by-step explanation:

With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0

As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.

At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)

we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.

we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔ m.

It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m

6 0

3 years ago

I don’t get this ughhhh I’m gonna quit

eimsori [14]

Where are you supposed to drag it?

3 0

4 years ago

the base of a rectangle has a length of 4 inches and a diagonal has a length of 5 inches, Find the area of the rectangle

Vaselesa [24]

This is just a highly educated guess it is 20 you multiply 5 by 4

8 0

3 years ago