I'll make you brainliest Easyquestion 6th grade multiply and add fractions pleaze answer it ASAP

What is the shape of this distribution

Len [333]

Answer is B. Hope this helps
Could I please get brainliest answer?

3 0

3 years ago

12. Cr

Zigmanuir [339]

The converted the percentage to a decimal the wrong way.

Move the decimal point 2 places to the left.

6.5% as a decimal is 0.065

525.05 x 0.065 = 34.13

X = 34.13

4 0

3 years ago

A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses p

gizmo_the_mogwai [7]

Answer:

$t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604$

$p_v =2*P(t_{(88)}>2.604)=0.0108$

So the p value is a very low value and using any significance level for given $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

$\bar X_{1}=9.1$ represent the mean for the sample 1

$\bar X_{2}=8$ represent the mean for the sample 2

$s_{1}=1.9$ represent the sample standard deviation for the sample 1

$s_{2}=2.1$ represent the sample standard deviation for the sample 2

$n_{1}=40$ sample size for the group 1

$n_{2}=50$ sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis: $\mu_{1} = \mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

$t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604$

Statistical decision

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=40+50-2=88$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{(88)}>2.604)=0.0108$

So the p value is a very low value and using any significance level for given $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0

3 years ago

Keith played the first 22 minutes of soccer game lohan then replaced him for the rest of half logan started the second half and

insens350 [35]

Answer:

Logan played for 22 minutes during the second half.

Step-by-step explanation:

Since Keith played the first 22 minutes of a soccer game and Logan then replaced him for the rest of the half, and Logan started the second half and was replaced by Wilson with 18 minutes left in the game, if each half is 40 minutes long To determine how long did Logan play during the second half, the following calculation must be performed:

Second Half Total - Time Played by Wilson = Time Played by Logan

40 - 18 = X

22 = X

Therefore, Logan played for 22 minutes during the second half.

6 0

2 years ago

Mrs. Powell has $800 invested in stocks and $500 invested in a Certificate of Deposit. The CD has an interest rate twice as grea

Mashutka [201]

Let's use the variable "r" to represent the investment rate of the stocks:
2r(500) + r(800) = 45
1000r + 800r = 45
1800r = 45
r = 0.025
2r = 0.05
The $500 is invested at 5%

7 0

3 years ago

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