Answer:
The average acceleration of train is 
Step-by-step explanation:
We have,
A train that slows down from 15 m/s to 8.6 m/s in 1.2 s. It means that 15 m/s is its initial velocity and 8.6 m/s is its final velocity.
It is required to find the average acceleration of the train.

The average acceleration of train is
. Negative signs shows that the train is decelerating.
Solutions
⇒9/12
1) To see if 9/12 is in simplest form you have to find 9 and 12's GCF.
The GCF of 9 and 12 is 3
2) Divide by the GCF
9 ÷ 3 = 3
12 ÷ 3= 4
3/4 is answer
Answer:
<h2><em><u>23</u></em><em><u> </u></em><em><u>days</u></em></h2>
Step-by-step explanation:
<em><u>Given</u></em><em><u>,</u></em>
No. of days taken by Jenny to read 7 books
= 8
<em><u>So</u></em><em><u>,</u></em>
No. of days taken by her to read 1 book

<em><u>Therefore</u></em><em><u>,</u></em>
No. of days taken by her to read 20 books

- <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

- <em>[</em><em>On</em><em> </em><em>dividing</em><em>]</em>
= 22.85.....
- <em>[</em><em>On</em><em> </em><em>approximating</em><em>]</em>
= 23 days (approx. )
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>Jenny</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>take</u></em><em><u> </u></em><em><u>23</u></em><em><u> </u></em><em><u>days</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>read</u></em><em><u> </u></em><em><u>20</u></em><em><u> </u></em><em><u>books</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
Solution:
<u>Simplify the equation and solve.</u>
- 89(54x − 36) + 2 = −34(−40 + 16x) + 90x
- => 4806x − 3204 + 2 = 1360 - 544x + 90x
- => 4806x = 1360 - 454x + 3202
- => 5260x = 4562
- => x = 4562/5260 = 2281/2630
The solution to the problem is 2281/2630.
Plug in the x value.
3(1-2)2=?
1-2= -1
3(-1)= -3
-3(2)= -6.
The answer is -6.