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Nady [450]
3 years ago
15

A piece of glass has a thin film of gasoline floating on it. A beam of light is shining perpendicular on the film. If the wavele

ngth of light incident on the film is 560 nm and the indices of refraction of gasoline and glass are 1.40 and 1.50, respectively, what is the minimum nonzero thickness of the film to see a bright reflection?
Computers and Technology
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:

200 nm

Explanation:

We need a constructive interference to see the bright reflection

we know that 2t=m\lambda  where m=1 and \lambda is the wavelength of the gasoline

so \lambda =\frac{560}{1.4}=400nm

putting the value of m and \lambda in thickness equation

t=\frac{1\times 400}{2}=200nm

so the thickness of the film will be 200 nm

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Aneli [31]

Answer:

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STANDART_DEDUCTION = 10000.0

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income = gross_income - STANDART_DEDUCTION - (DEPENDENT_DEDUCTION * number_of_dependents)

tax = income * TAX_RATE

print ("The income tax is $" + str(round(tax, 2)))

Explanation:

Define the <em>constants</em>

Ask user to enter the <em>gross income</em> and <em>number of dependents</em>

Calculate the <em>income</em> using formula (income = gross_income - STANDART_DEDUCTION - (DEPENDENT_DEDUCTION * number_of_dependents))

Calculate the <em>tax</em>

Print the <em>tax</em>

<em />

round(number, number of digits) -> This is the general usage of the <em>round</em> function in Python.

Since we need <u>two digits of precision</u>, we need to modify the program as str(<u>round(incomeTax, 2</u>)).

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Answer:

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Answer:

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Answer:

#include <iostream>

using namespace std;

int main()

{

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}

Explanation:

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using namespace std;

Says to compiler we are using std.

int main() Main function

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Have a nice day ;)

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