So basicly the question is asking, name 4 parrelegrams. Thr answer will be, Rectangle, Squrare Trapizoid, and Rhymbus. Not is a specifc order.
Answer: According to Newton s Second Law of Motion, also known as the Law of Force and Acceleration, a force upon an object causes it to accelerate according to the formula net force = mass x acceleration. So the acceleration of the object is directly proportional to the force and inversely proportional to the mass.
Step-by-step explanation:
Answer:
6x - 15
Step-by-step explanation:
f(x) = 2x + 3 and g(x) = 3x - 9.
![f(g(x))=2(3x-9)+3\\f(g(x))=6x-18+3\\f(g(x))=6x-15](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D2%283x-9%29%2B3%5C%5Cf%28g%28x%29%29%3D6x-18%2B3%5C%5Cf%28g%28x%29%29%3D6x-15)
She would need to score 16 correct answers, because 80/5 = 16.
Answer:
1857.12 square meters
Step-by-step explanation:
Let L be the length of the rectangle and 'W' be the width
Perimeter = ![2L + 2W + 2W](https://tex.z-dn.net/?f=2L%20%2B%202W%20%2B%202W)
The fencing material costs $30 per meter.
The material for the partitions costs $25 per meter
![cost=30(2L + 2W) +25( 2W)\\60L+60W+50W\\60L +110W](https://tex.z-dn.net/?f=cost%3D30%282L%20%2B%202W%29%20%2B25%28%202W%29%5C%5C60L%2B60W%2B50W%5C%5C60L%20%2B110W)
![7000=60L+110W](https://tex.z-dn.net/?f=7000%3D60L%2B110W)
Solve for L
![7000=60L+110W\\7000-110W= 60L\\L=\frac{700}{6} -\frac{11}{6} W](https://tex.z-dn.net/?f=7000%3D60L%2B110W%5C%5C7000-110W%3D%2060L%5C%5CL%3D%5Cfrac%7B700%7D%7B6%7D%20-%5Cfrac%7B11%7D%7B6%7D%20W)
Area = length times width
![( \frac{700}{6} -\frac{11}{6} W)(W)\\A(W)=\frac{700}{6}W -\frac{11}{6} W^2](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B700%7D%7B6%7D%20-%5Cfrac%7B11%7D%7B6%7D%20W%29%28W%29%5C%5CA%28W%29%3D%5Cfrac%7B700%7D%7B6%7DW%20-%5Cfrac%7B11%7D%7B6%7D%20W%5E2)
Now take derivative and set it =0
![A(W)=\frac{700}{6}W -\frac{11}{6} W^2\\A'(W)=\frac{700}{6} -\frac{22}{6} W](https://tex.z-dn.net/?f=A%28W%29%3D%5Cfrac%7B700%7D%7B6%7DW%20-%5Cfrac%7B11%7D%7B6%7D%20W%5E2%5C%5CA%27%28W%29%3D%5Cfrac%7B700%7D%7B6%7D%20-%5Cfrac%7B22%7D%7B6%7D%20W)
set the derivative =0 and solve for W
![0=\frac{700}{6} -\frac{22}{6} W\\\frac{700}{6}=\frac{22}{6} W\\W= 31.8](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B700%7D%7B6%7D%20-%5Cfrac%7B22%7D%7B6%7D%20W%5C%5C%5Cfrac%7B700%7D%7B6%7D%3D%5Cfrac%7B22%7D%7B6%7D%20W%5C%5CW%3D%2031.8)
So width = 31.8 that gives maximum area
![L=\frac{700}{6} -\frac{11}{6} (31.8)=58.4](https://tex.z-dn.net/?f=L%3D%5Cfrac%7B700%7D%7B6%7D%20-%5Cfrac%7B11%7D%7B6%7D%20%2831.8%29%3D58.4)
square meter