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scoundrel [369]
4 years ago
12

Last month Ben spent $380 on food and $420 on personal items. What percent of his monthly income did he spend on these items?​

Mathematics
2 answers:
goblinko [34]4 years ago
6 0

Answer:

Ben spent $800

Step-by-step explanation:

simple math

kykrilka [37]4 years ago
6 0

He makes 4000 per month.

380 + 420 = 800

800/4000 = 0.20

0.20 * 100 = 20

He spent 20% of his monthly income on those items.

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2.21 is 2.5% of what
Bad White [126]
So first to solve this you divide it by 2.5 to get what 1% is: this would be 0.884.
Then to get 100% of the number you multiply 0.884 by 100. The answer to that is 88.4.
2.21 is 2.5% of 88.4, hope this helps!
6 0
4 years ago
Y<br><img src="https://tex.z-dn.net/?f=y%20%20%5Cgeqslant%20%20%20-%205x%20%2B%20%203" id="TexFormula1" title="y \geqslant -
masha68 [24]
Okay so at first it was confusing because I didn't know what you were asking but I'm Guessing you wanted it graphed and shaded so here you go. 

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3 0
4 years ago
A medical equipment industry manufactures X-ray machines. The unit cost C (the cost in dollars to make each X-ray machine) depen
earnstyle [38]

Answer:

$11988

Step-by-step explanation:

Given that,

The unit cost is given by :

C(x)=0.7x^2-462x+88218

We need to find the minimum unit cost.

For minimum cost,

Put \dfrac{dC}{dx}=0

So,

\dfrac{d}{dx}(0.7x^2-462x+88218)=0\\\\1.4x-462=0\\\\x=\dfrac{462}{1.4}\\\\x=330

Put x = 330 in equation (1).

C(330)=0.7(330)^2-462(330)+88218\\\\=\$11988

So, the minimum unit cost is equal to $11988.

5 0
3 years ago
It is known that 10% of the 9-year old children in a town have three siblings. Fifteen 9-year old children are selected at rando
inn [45]

Using the binomial distribution, it is found that there is a 0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, for the parameters, we consider that:

  • 10% of the 9-year old children in a town have three siblings, hence p = 0.1.
  • Fifteen 9-year old children are selected at random, hence n = 15.

The probability that more than 3 of these selected children have three siblings is given by:

P(X > 3) = 1 - P(X \leq 3)

In which:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059

P(X = 1) = C_{15,1}.(0.1)^{1}.(0.9)^{14} = 0.3432

P(X = 2) = C_{15,2}.(0.1)^{2}.(0.9)^{13} = 0.2669

P(X = 3) = C_{15,3}.(0.1)^{3}.(0.9)^{12} = 0.1285

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.2059 + 0.3432 + 0.2669 + 0.1285 = 0.9445

P(X > 3) = 1 - 0.9445 = 0.0555

0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.

More can be learned about the binomial distribution at brainly.com/question/24863377

5 0
2 years ago
What is the product.... <br><br> (1.017)•(0.072)=
tester [92]
0.073224 is the answer
8 0
3 years ago
Read 2 more answers
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