Answer:
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Step-by-step explanation:

Formula used =
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Answer:
15/4 and 45/4
Step-by-step explanation:
Let x and y be the numbers
x = 3y
x+ y = 15
Substitute the first equation in to the second equation
3y+y = 15
4y = 15
y = 15/4
x = 3(15/4)
x = 45/4
The two numbers are 15/4 and 45/4
F(x)=5/x
g(x)=2(x^2)+5x
f(x) has a domain of all real numbers excluding zero
g(x) has a domain of all real numbers
fog(x)=5/(2(x^2)+5x)
fog(x)=5/(x(2x+5))
fog(x) has a domain that excludes both zero and -5/2
Answer:
10. 23
11. -17
12. 0
13. -4
14. -6
15. 4
Explanation:
10. 8+15= 23
11. -8-9= -17
12. 8-8= 0
13. -8+4= -4 (same as 4-8)
14. -10+4= -6 (same as 4-10)
15. 12-8= 4
Answer:
LM = 18
Step-by-step explanation:
BC = 4
CD is twice that, so CD is 8
Now, remembering that the area of ABCD = 32 and JKLM = 72, divide 72 by 32.
You get 2.25. This is how much bigger JKLM is than ABCD.
Using that, multiply the length of CD (which is 8) by 2.25 to get the length of LM.
You'll get 18.
Hope this helps!