Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
He will need exactly 24 stickers. To get this number, you must multiply both sides. :)
135
cross multiply 9*20 then divide by 8
Answer:
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Step-by-step explanation:
Required
Show that:
To make the proof easier, I've added a screenshot of the triangle.
We make use of alternate angles to complete the proof.
In the attached triangle, the two angles beside 
are alternate to 
and 
i.e.
Using angle on a straight line theorem, we have:
Substitute values for (1) and (2)
Rewrite as:
<em></em><em> -- proved</em>
Answer:
-1+2x= 17
2x=18
x=9
Step-by-step explanation:
ans. 9
