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anyanavicka [17]
3 years ago
9

PLEASE HELP 30 POINTS DONT HAVE TO SHOW WORK 3 ATTACHMENTS PLEASE ANSWER ALL

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0
First one answer is C.
log3(1/81) = -4

-------------
log(45) / log(2) = 5.4919

answer
A. 5.4919
--------------------
next step
x - 1 = 3x+9
2x - 10
x = -5

answer
D. x - 1 = 3x+9

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B/5 -34<-41 what is B
snow_tiger [21]

Answer:

b<-35

Step-by-step explanation:

b/5-34<-41

b/5<-41+34

b/5<-7

b<-7*5

b<-35

4 0
3 years ago
A single batch of cookies requires two cups of sugar and three cups of flour. If more than one batch or a partial batch was made
HACTEHA [7]

Step-by-step explanation:

4 cup of sugar = 6 cup of flour

4.5 cup of sugar = 6.75 cup of flour

5 cup of sugar = 7.5 cup of flour

7.5 cup of sugar = 11.25 cup of flour

8 cup of sugar = 12cup of flour

hope it helps you

6 0
2 years ago
Read 2 more answers
5. 4i(-2 - 4i)
Wewaii [24]

Answer:

4i( - 2 - 4i) =  - 8i + 16 \\  \\ 5i.i.( - 2i) = 10i \\  \\  (- 5 - i)(1 + i) =  -5-5i-i+1\\=-4-6i

4 0
2 years ago
Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0
3 years ago
Which statement is true about the given expression? A. The "11" in the second term is a constant. B. The "4" in the third term i
lyudmila [28]

Answer:

a

Step-by-step explanation:


7 0
3 years ago
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