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astra-53 [7]
3 years ago
15

Tyler has a bag of shapes with 8 octagons, 24 trapezoids, 5 pentagons, 14 hexagons what is the probability he will pick a shape

with more than 5 sides
Mathematics
1 answer:
lana [24]3 years ago
5 0
More than 5 sides have octagons and hexagons
so 
8+14=22
altogether  8+14+24+5 =22+29=51
P=22/51
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the sum of the digits of a two digit number is 8. the number obtained by interchanging the digits exceeds the original number by
Sedbober [7]

Heya friend,

------------------------------------------------------

Let the digits at ones place be x. Then,

the digits at tens place = (8-x)

Original number = 10(8-x) + x

= 80 - 10x + x

= 80 - 9x

On interchanging the digits

new number obtained = 10x + 8-x

= 9x + 8

According to question,

New number - Original number = 18

9x + 8 - (80-9x) = 18

=> 9x + 8 - 80 + 9x = 18

=> 18x - 72 = 18

=> 18x = 18 + 72

=> 18x = 90

=> x = 90/18

=> x = 5

Hence, the digits at ones place is 5.

The digits at tens place = (8-5) = 3.

So, the original number is 35 and the new number is 53.

Thanks

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What's the volume of the cone?
dmitriy555 [2]
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So C.
7 0
3 years ago
Write 9,150,000 in scientific notation
inna [77]

Answer:

9.15x10^6

Step-by-step explanation:

7 0
3 years ago
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What is 4/3 plus 3/4
skelet666 [1.2K]
4/3 + 3/4
Make the denominator the same: 12
16/12 + 9/12
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7 0
3 years ago
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Vaselesa [24]

Answer:

\frac{9}{16}

Step-by-step explanation:

Let total number of students=x

Students went to the book fair:

Students went to book fair=\frac{15}{20}\times total\ number\ of\ students=\frac{15}{20}x

Students who bought book:

Students\ who\ bought\ book=\frac{12}{16}\times Number\ of\ students\ went\ to\ book\ fair=\frac{12}{16}\times \frac{15}{20}x=\frac{9}{16}x

Hence \frac{9}{16} of total students bought at least one book.

3 0
4 years ago
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