Answer:

![\textsf{Range}: \quad [-3,3] \quad -3\leq y\leq 3](https://tex.z-dn.net/?f=%5Ctextsf%7BRange%7D%3A%20%5Cquad%20%5B-3%2C3%5D%20%5Cquad%20-3%5Cleq%20y%5Cleq%203)
Step-by-step explanation:
The domain of a function is the set of all possible input values (x-values).
The range of a function is the set of all possible output values (y-values).
<u>Interval notation</u>
- ( or ) : Use parentheses to indicate that the endpoint is excluded.
- [ or ] : Use square brackets to indicate that the endpoint is included.
<u>Inequality notation</u>
- < means "less than".
- > means "more than".
- ≤ means "less than or equal to".
- ≥ means "more than or equal to".
From inspection of the given graph, the function is continuous and so the domain is <u>not</u> restricted.
Therefore, the domain of the function is:
- Interval notation: (-∞, ∞)
- Inequality notation: -∞ < x < ∞
From inspection of the given graph, the minimum value of y is -3 and the maximum value of y is 3. Both values are included in the range.
Therefore, the range of the function is:
- Interval notation: [-3, 3]
- Inequality notation: -3 ≤ y ≤ 3
Answer: there is a proplem in here
oi
Step-by-step explanation:
5.11, i used the produatecr formula
Answer:
11
Step-by-step explanation:
f(1) = 3(1) + 8 = 3 + 8 = 11
Answer:
As Given, x+y=w+z
To Prove: AOB is a line or x+y=180
∘
(linear pair.)
According to the question,
x+y+w+z=360
∘
∣ Angles around a point.
(x+y)+(w+z)=360
∘
(x+y)+(x+y)=360
∘
∣ Given x+y=w+z
2(x+y)=360
∘
(x+y)=180
∘
Hence, x+y makes a linear pair.
Therefore, AOB is a straight line