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mel-nik [20]
3 years ago
14

Expression tha have the same vaule

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0
I don't know if this is the answer that you are looking for, but would the answer be all solutions?
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You accept a new job with a starting salary of $47,000. You receive a 4% raise at the start of your second year, a 5.6% raise at
Sunny_sXe [5.5K]

Answer:

1yr  47,000, 2nd yr  48,880, 3rd yr   51,617.28, 4th yr  57,346.7981 or 57,346.80

Step-by-step explanation:

1yr        47,000

2nd yr  47,000 x 4% = 48,880

3rd yr   48,880 x 5.6% = 51,617.28

4th yr   51,617.28 x 11.1% = 57,346.7981 or 57,346.80

4 0
2 years ago
Write a recursive formula for an, the nth term of the sequence 3, -4, -11
yKpoI14uk [10]

Answer:

, 12, 48, 192...

a. Write a recursive formula for the nth term of the sequence

Ans: a(n+1) = 4*a(n)

------------------------------

b. Write a general formula for the nth term of the sequence

a(n) = 3*4^(n-1)

--------------

c. Calculate S10 for this sequence

Geometric sequence with a(1) = 3 and r = 4

----?

Step-by-step explanation:

8 0
2 years ago
32/160 as a simplified fraction someone help coz I'm clueless with fractions
omeli [17]

32÷2/160÷2

=16÷2/80÷2

8÷2/40÷2

4÷2/20÷2

2÷2/10÷2

1/5

4 0
3 years ago
Read 2 more answers
For the rotation - 660°, find the coterminal angle from 0° < 0 < 360°, thequadrant and the reference angle.
guajiro [1.7K]

Given the angle:

-660°

Let's find the coterminal angle from 0≤θ≤360.

To find the coterminal angle, in the interval given, let's keep adding 360 degrees to the angle until we get the angle in the interval,

We have:

Coterminal angle = -660 + 360 = -300 + 360 = 60°

Therefore, the coterminal angle is 60°.

Since 60 degrees is between 0 to 90 degrees, is is quadrant I.

60 degrees lie in Quadrant I.

Also since it is in quadrant I, the reference angle is still 60 degrees.

ANSWER:

The coterminal angle is 60°, which lies in quadrant I, with a reference angle of 60°

3 0
11 months ago
PLEASE ANSWER ASAP! YOUR ANSWER MUST REQUIRE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER!!! THANKS!!!
KIM [24]
Hello,

Using vectors and scalar product:

[(a+c)*\vec{i}+(b-0)*\vec{j} ].[(a-c)*\vec{i}+(b-0)*\vec{j}]=0
Thus
\dfrac{b^2}{(a+c)(a-c)}=1

By the way how can we make text larger in latex \larger{.....} don't work.

Answer A




8 0
3 years ago
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