All categories

3 years ago

How do you solve the problem 3/4 of 28

Mathematics

2 answers:

posledela3 years ago

4 0

The answer is 3/4 of 28 is 21

defon3 years ago

3 0

Answer: 21

Step-by-step explanation: .75 x 28

You might be interested in

Information on a packet of seeds, which may not be a random sample of seeds, claims that the germination rate is 94%. What's

Evgesh-ka [11]

Answer:

0.1052

Step-by-step explanation:

Given that proportion of germination in the population is 94% =0.94

p = 0.96

Sample size = 220

Std dev of p = $\sqrt{\frac{pq}{n} } \\=0.016$

The probability that more than 96% of the 220 seeds in the packet will germinate

= $P(p\geq 0.96)\\=P(Z\geq \frac{0.96-0.94}{0.016})\\=P(Z\geq 1.25)\\==1-0.8948\\=0.1052$

Assumptions are np and nq >5 and also sample size >220 hence normal

7 0

3 years ago

504 books a week so how many books a hour

Effectus [21]

<span>2.98214285714 an hour for 168 hours</span>

8 0

3 years ago

Read 2 more answers

Pls need help 100 points and crown if right!!!

nekit [7.7K]

Answer:

$\sf 2\dfrac{1}{4}\ cups \ of \ sugar$

Explanation:

Let the full batch be x

Here given:

3/4 cup of sugar required to make 1/3 batch of cookies

Build equation:

$\sf \rightarrow \dfrac{1}{3}x = \dfrac{3}{4} \ cup \ of \ sugar$

Solve:

$\sf \rightarrow x = \dfrac{3(3)}{1(4)}$

$\sf \rightarrow x = \dfrac{9}{4}$

$\rightarrow \sf x = 2\dfrac{1}{4}$

5 0

1 year ago

Read 2 more answers

Which line is the best model for the data in the scatter plot?

brilliants [131]

Yeah the first one (A) seems like the best to me :)

4 0

3 years ago

Read 2 more answers

If you can explain your answer that’d be great!! Thank you!

Rasek [7]

Answer:

$A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}$

Step-by-step explanation:

This half life exponential decay equation goes by the formula:

$A(t)=A_{0}e^{kt}$

Where

$k=\frac{ln(\frac{1}{2})}{Half-Life}$

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:

So,

$k=\frac{ln(\frac{1}{2})}{Half-Life}\\k=\frac{ln(\frac{1}{2})}{22}$

Now

$A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}$

third choice is correct.

8 0

3 years ago