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NNADVOKAT [17]
3 years ago
11

Solve x^2-3x=-8 PLEASE HELP ALGEBRA 2

Mathematics
1 answer:
Delvig [45]3 years ago
5 0

Answer:

idk aljebra 2 either and i just got the same question how?

Step-by-step explanation:

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Please solve the whole page
Levart [38]

Answer:

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6 0
2 years ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS IF YOU ANSWER WITH A LINK YOU WILL GET REPORTED!!!!!!
kolbaska11 [484]

Answer:

1,5

Step-by-step explanation:

The translation can be seen in one line. You can see one going up by 5 and going to the right (not left as that would make it -1,5).

7 0
2 years ago
ILL GIVE U BRAINLESS I NEEED THE ANSWER ASAP LOL
Bogdan [553]

Answer:

what is the question

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Andrea is given triangle ABC and told that a ^ 2 + b ^ 2 = c ^ 2 draws right triangle RTS with legs measuring a and b and hypote
kondaur [170]

Complete question is;

Andrea is given ABC and told that a² + b² = c². She draws right triangle RTS with legs measuring a and b and hypotenuse measuring 2. Which best describes what Andrea should

do in order to prove that ABC is a right triangle?

Answer:

Andrea should show that c = 2, so: ∡ABC = ∡RTS and ∡C = ∡S. Hence, ∡C is a right angled triangle, hence ΔABC is a right triangle

Step-by-step explanation:

In this question, we are told that the given sides of the triangle are a, b and c. Now, Andrea is able to draw the two sides of the right triangle with sides = a and b and the third, hypotenuse equal to 2. Since the length of the hypotenuse = 2, then we have;

2² = a² + b²

However, we are told that c² = a² + b²

Therefore, c = 2

Hence, Andrea should show that c = 2 so ΔABC = ΔRTS and ∡C = ∡S hence ∡C is a right angled triangle since it is the angle opposite to the hypotenuse c and therefore, ΔABC is a right triangle.

8 0
3 years ago
F(x) = 3 sin x + 3 cos x
Darina [25.2K]
F ( x ) = 3 sim x + 3 cos x
f ` ( x ) = 3 cos x - 3 sin x
f `` ( x ) = - 3 sin x - 3 cos x = - 3 ( sin x + cos x )
The inflection points:
- 3 ( sin x + cos x ) = 0
sin x + cos x = 0
sin x = - cos x / : cos x
tan x = - 1
x 1 = 3π / 4
x 2 = 7π / 4
The function is concave up when f``(x) > 0
- 3( sin x+ cos x ) > 0
sin x + cos x < 0
tan x < - 1
f is concave up for:
x ∈ ( π/2, 3π/4 ) ∪ ( 3π/2, 7π/4)
f is concave down for: 
x ∈ ( 0, π/2 ) ∪ ( 3π / 4, 3π/2 ) ∪ ( 7π / 4, 2 π ).
5 0
3 years ago
Read 2 more answers
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