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cestrela7 [59]
3 years ago
13

Is it possible to combine multiple discounts that are less than 100% off so that an item is 100% off and essentially free?

Mathematics
1 answer:
Mkey [24]3 years ago
5 0
Sort of, say you take 99% off of something that is $100. You will end up paying $1. Then if you take another 99% off, you wil pay $0.01. Takig another 99% off will give you $0.001, but money only goes to two decimal points, so its free from a money standpoint, but there is still a cost.
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A scale drawing of a school playground in the shape of a rectangle is shown. What is the area in square meters of the playground
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8×19= 152  

1 : 4.5  

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What is the constant of proportionality in the equation x/y=2/9<br> HURRY
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Step-by-step explanation:

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3 years ago
A manufacturing facility is responsible for producing two components that are produced at states 1 (poor), 2 (below average), 3
garik1379 [7]

Answer:

a) i) P( final product is acceptable ) = 3/5

   ii) P ( final product not acceptable ) =  2/5

B)  P (  final product is acceptable | X =2 ) = 2/5

C)  P ( Y = 3 | Final product is acceptable ) = 2/5

Step-by-step explanation:

Given data :

5 states : 1 (poor), 2 (below average), 3 (average), 4 (good), and 5 (excellent)

Number of components produced = 2

X ( component 1 ) ∴ P(X) = 1/5

Y ( component 2 ) ∴ P(Y) = 1/5

Aim : Sum of Final product needs to be ≥ 6

<u>A) Probability of a final product been acceptable and also unacceptable</u>

P( final product is acceptable ) ; P(X + Y ≥ 6 )

= 1/5 ∑ P( Y ≥ 6 - x )

= 1/5 ( P( Y ≥ 5 ) + P( Y ≥ 4 ) + P( Y ≥ 3 ) + P( Y ≥ 2 ) + P( Y ≥ 1 )

= 1/5 ( 1/5 + 2/5 + 3/5 +4/5 + 1 )

= 3/5

P ( final product not acceptable ) = 1 - 3/5 = 2/5

B) P (  final product is acceptable | X =2 )

 ∴ P ( Y ≥ 4 )

   = 2/5

C) P ( Y = 3 | Final product is acceptable )

∴ P ( X ≥ 3 ) ≠ P( Y ≥ 3 )  ( because they are not independent )

  = 1 - 3/5 = 2/5.

8 0
3 years ago
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