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2 years ago

How do I find A’? Let U={a,b,c,d,e,f,g} and A={a,b,e,f}

Mathematics

1 answer:

vesna_86 [32]2 years ago

6 0

Let U={a,b,c,d,e,f,g,h}

A={a,c,d}

B={b,c,d}

C={b,e,f,g,h}

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X^3+x²-36 Find all real zeros.

Harman [31]

Answer: x=3

Step-by-step explanation:

To find the zeros, you want to first factor the expression.

x³+x²-36

(x-3)(x²+4x+12)

Now that we have found the factors, we set each to 0.

x-3=0

x=3

Since x²+4x+12 cannot be factored, we can forget about this part.

Therefore, the zeros are x=3. You can check this by plugging the expression into a graphing calculator to see the zeros.

4 0

3 years ago

Suppose that Y varies directly with X andY equals 12 when X equals -2 what is X when Y equals -6

VLD [36.1K]

Answer:

$x=1$

Step-by-step explanation:

A direct variation equation has the following format:

$y=kx$

Where k is a constant.

We know that y is 12 when x is -2. Thus, substitute:

$12=-2k$

Divide both sides by -2:

$k=-6$

So, our direct variation equations is:

$y=-6x$

To find what x is when y equals -6, substitute in -6 for y:

$-6=-6x$

Divide both sides by -6:

$x=1$

So, our answer is 1 :)

4 0

3 years ago

Help me I don't know what is 10=n+19

Orlov [11]

Answer: n=-9

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

In ΔDEF, what is sin D, in simplified form?

Igoryamba

Answer: second option.

Step-by-step explanation:

You must apply $sin\alpha=\frac{opposite}{hypotenuse}$

Then, given the right triangle and the angle D, the opposite side and the hypotenuse of the triangle are the following:

$opposite=20\\hypotenuse=25$

Therefore, when you substitute values, you have:

$sinD=\frac{20}{25}$

Reduce the fraction, then you obtain:

$sinD=\frac{4}{5}$

5 0

3 years ago

Read 2 more answers

What is the range of the function f(x) = 12 − 3x for the domain {-4, -2, 0, 2, 4}?

Sphinxa [80]

Answer:

{24, 18, 12, 6, 0} is the range of the above function

Step-by-step explanation:

solution:

let, x= -4

f(-2) = 12-3*(-2)

= 12+12

=24

let,x= -2

f(-2) = 12-3*(-2)

=12+6

let,x =0

f(0)= 12-3*0

=12-0

=12

let,x=2

f(2) = 12-3*2

=12-6

let,x=4

f(4) = 12-3*4

=12-12

4 0

2 years ago