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worty [1.4K]
3 years ago
5

Rewrite the expression 5(6 + 9) as the sum of 30 and another whole number.

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
5 0

Answer:

30 + 45

Step-by-step explanation:

5(6 + 9) = 5*6 + 5*9 = 30 + 45

lapo4ka [179]3 years ago
4 0

Answer:

30 +45

Step-by-step explanation:

5(6 + 9)

Distribute the 5

5*6 +5*9

30 +45

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A roller coaster's height from the ground is modeled by r(t) = 4sin(4t)+25 where t is time in minutes. A Ferris wheel's height f
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3 years ago
A= 1,321 +0.3433m
noname [10]

Answer:

Option A: For each increase of 1 gram in mass, A increases by approximately 0.3433 square centimeter.

Step-by-step explanation:

We are given the function;

A= 1321 + 0.3433m

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7 0
3 years ago
I really stuck on trying to prove this
Alisiya [41]
\displaystyle\sum_{r=1}^nr(r+1)\cdots(r+p-1)

When n=1,

\displaystyle\sum_{r=1}^1r(r+1)\cdots(r+p-1)=1(1+1)(1+2)\cdots(1+p-2)(1+p-1)=p!

Meanwhile, you have on the right

\dfrac{(1)(1+1)(1+2)\cdots(1+p-2)(1+p-1)(1+p)}{p+1}=(1)(1+1)(1+2)\cdots(p-1)(p)=p!

so the equality holds for n=1.

Assume it holds for n=k, i.e. that

\displaystyle\sum_{r=1}^kr(r+1)\cdots(r+p-1)=\frac{k(k+1)(k+2)\cdots(k+p-1)(k+p)}{p+1}

Now for n=k+1, you have

\displaystyle\sum_{r=1}^{k+1}r(r+1)\cdots(r+p-1)=\sum_{r=1}^kr(r+1)\cdots(r+p-1)+(k+1)(k+2)\cdots(k+1+p-1)
=\displaystyle\frac{k(k+1)(k+2)\cdots(k+p-1)(k+p)}{p+1}+(k+1)(k+2)\cdots(k+1+p-2)(k+1+p-1)
=\displaystyle\frac{k(k+1)(k+2)\cdots(k+p-1)(k+p)}{p+1}+(k+1)(k+2)\cdots(k+p-1)(k+p)
=\left(\dfrac k{p+1}+1\right)(k+1)(k+2)\cdots(k+p-1)(k+p)
=\dfrac{k+p+1}{p+1}(k+1)(k+2)\cdots(k+p-1)(k+p)
=\dfrac{(k+1)(k+2)\cdots(k+p-1)(k+p)(k+p+1)}{p+1}

as required.
3 0
3 years ago
5X - 2X + 7 - X = no solution
saveliy_v [14]
If you simply the expression it would give you 2x+7 .
3 0
3 years ago
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