4(60q-190u-13b+17i) you have to factor the polynomials
Answer:
a = 7
Step-by-step explanation:
Using the rule of radicals
×
= ![\sqrt{ab}](https://tex.z-dn.net/?f=%5Csqrt%7Bab%7D)
Given
(
+
)
Distribute parenthesis by ![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
=
+ ![\sqrt{5(32)}](https://tex.z-dn.net/?f=%5Csqrt%7B5%2832%29%7D)
=
+ ![\sqrt{160}](https://tex.z-dn.net/?f=%5Csqrt%7B160%7D)
=
+ ![\sqrt{16(10)}](https://tex.z-dn.net/?f=%5Csqrt%7B16%2810%29%7D)
=
×
+
× ![\sqrt{10}](https://tex.z-dn.net/?f=%5Csqrt%7B10%7D)
= 3
+ 4![\sqrt{10}](https://tex.z-dn.net/?f=%5Csqrt%7B10%7D)
= 7
⇒ a = 7
Hello! This is actually pretty easy to solve, all you have to do is subtract 28.65 from 24.25 So when you subtract 5 from 5, you get zero. When you subtract 6 from 2, you get 4. When you subtract 8 from 4, you get 4, and when you subtract 2 from 2 you get zero. So all you do is take out the zeros and put the decimal point in the same place it was in before, and this should leave you with your answer!
I hope this helped!
I am, yours most sincerely,
SuperHelperThingy
Answer:
it will take t= 12.64 seconds
Step-by-step explanation:
the voltage drop rate dV/dt will be
dV/dt=-k*V
then
∫dV/V=∫-kdt
ln(V/V₀)= -k*t
V=V₀*e^(-k*t)
in order for the voltage to drop 10 percent of its original value , then
(V₀-V)/V₀= 0.1 (10%)
[V₀- V₀*e^(-k*t) ] / V₀ = 0.1
1 - e^(-k*t) = 0.1
e^(-k*t) = 0.9
t = (- ln 0.9)/k = 120* (- ln 0.9) = 12.64 seconds
t= 12.64 seconds
Each batch gives you 3 dozen and you need 1 1/2 cups for each batch of cookies
she uses 6 cups in total, so divide 6 by 1 1/2 to get the number of batches
6 ÷ 1 1/2 = 4 batches
so 4 batches × 3 dozen cookies = 12 dozen cookies