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Dovator [93]
4 years ago
7

3. Given BP= 7in and CB = 9in, what is AC?

Mathematics
1 answer:
DiKsa [7]4 years ago
5 0

Answer:

AC = 9 in

Step-by-step explanation:

We have two triangles

Triangle APC  and triangle BPC

Side AP = side BP

Side CP is common

Angle P is also common

So side , angle and side are same for both triangles

Two sides are same for both triangles and included angle is also same

So they are congruent

Triangle APC is congruent to  triangle BPC

Hence AC = CB

BC= 9 inches

So AC = 9 inches

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Answer:

3 years, 11 months and 10 days

Step-by-step explanation:

Beethoven wrote

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3 years ago
KG passes through the point (2, 14) and intersects HG at the point (12, 4). If the point H(18, 10) lies on HG, write the equatio
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The equation for KG would be y-14=-1(x-2) and the equation for HG would be y-4=1(x-12).

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