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3 years ago

Can someone help me please which one is it ? A B C D

Mathematics

1 answer:

Leni [432]3 years ago

6 0

∠1 and ∠3 are complementary,
∠1 = ∠2,
so
∠2 and ∠3 are complementary.

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Aidan makes 12 bracelets on Monday. He makes 8 more bracelets each day from Tuesday through Thursday. How many bracelets does Ai

BARSIC [14]

Answer:

On Friday he did not make any bracelets He makes 8 more bracelets each day from Tuesday through Thursday

Step-by-step explanation:

He made 12 bracelets on Monday

For 3 days (from Tuesday to Thursday) he added 8 more each day)

8*3=24

24+12 = 36

M =12

T= 20 (12+8)

W=28(20+8)

Th=36(28+8)

F=36 (still has 36 because on Friday he did not make 8 more bracelets)

8*3=24

24+12 = 36

6 0

4 years ago

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Solve for x: x³=23 Choose all that apply: ∛23 3 1 23/3

rosijanka [135]

Your answer is A. I have attached a photo of an explanation

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2 years ago

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How many milliliters is in 50 liters of gas

mojhsa [17]

50000 millilitres Is in 50 liters of gas.

8 0

4 years ago

Use the discriminant to describe the roots of each equation. Then select the best description.

exis [7]

Answer:

Hello My Friend! The correct answer its double root.

Step-by-step explanation:

In this equation, if we applie the a, b and c coefficients (a=1, b=4, c=4) ind the Bhaskara, the final result will be 4 for both cases. x'=4 and x''=4. It happens because the number of theta is equal to 0. So, both roots will be the same number.

3 0

3 years ago

A hospital recorded the weights, in ounces, of newborn babies for two weeks. The

Gwar [14]

Answer:

The standard deviation for week two was about 3 ounces more than the standard deviation for week one

Step-by-step explanation:

Given

$Week\ 1: 128, 105, 80, 82, 96, 98, 87, 100, 112, 126$

$Week\ 2: 75, 85, 90, 97, 89, 105, 110, 127, 129, 130$

See attachment for options

Required

The true statement

Checking the standard deviation

For week 1

Calculate the mean:

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{128+ 105+ 80+ 82+ 96+ 98+ 87+ 100+ 112+ 126}{10}$

$\bar x = \frac{1014}{10}$

$\bar x_1 = 101.4$

Then standard deviation

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}$

$\sigma_1 = \sqrt{\frac{(128 - 101.4)^2 +............+ (126- 101.4)^2}{10}}$

$\sigma_1 = \sqrt{\frac{2522.4}{10}}$

$\sigma_1 = \sqrt{252.24$

$\sigma_1 = 15.88$

For week 2, we have:

$\bar x = \frac{75+ 85+ 90+ 97+ 89+ 105+ 110+ 127+ 129+ 130}{10}$

$\bar x = \frac{1037}{10}$

$\bar x_2 = 103.7$

Then standard deviation

$\sigma_2 = \sqrt{\frac{(75 - 103.7)^2 +................+ (130- 103.7)^2}{10}}$

$\sigma_2 = \sqrt{\frac{3538.1}{10}}$

$\sigma_2 = \sqrt{353.81$

$\sigma_2 = 18.81$

Compare the standard deviations

$\sigma_1 = 15.88$

$\sigma_2 = 18.81$

Calculate the difference:

$d = \sigma_2 - \sigma_1$

$d = 18.81 - 15.88$

$d = 2.93$

$d \approx 3$

This implies that option (b) is true

4 0

3 years ago