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3 years ago

Complete the equation -6×^2+15×-6=-3(2×-1)(×+_)

Mathematics

1 answer:

Wittaler [7]3 years ago

7 0

-6x^2 + 15x -6 =
-3(2x^2 -5x +2) =

-3(2x - 1)(x - 2)

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How many solutions are there to the following equation?

swat32

Answer:

D, infinitely many solutions

Step-by-step explanation:

1. multiply out

5(x-3) = 5x-15

2. combine like terms

5x-15-3x=8x-15-6x = 2x-15=2x-15

they are equal so there are infinite solutions.

8 0

3 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

3 years ago

What is the coefficient in the expression 5 plus 9y

Dovator [93]

Answer: y

Step-by-step explanation:

4 0

4 years ago

What’s the answer please

Liono4ka [1.6K]

Answer:

to know what scale to use you divide the the highest score by the number of hozirontal line (feint/lighter drawn lines) which are 14.

so 260 ÷ 14 equals = 18.57

I then rounded the 18.57 to the nearest 10th = 20.

so the scale used is 20s

5 0

2 years ago

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is

insens350 [35]

Answer:

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

Step-by-step explanation:

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is less than 0.16.

This means that the null hypothesis is:

$H_{0}: p \geq 0.16$

Testing this hypothesis, means that the alternate hypothesis is:

$H_{a}: p > 0.16$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.16 is tested at the null hypothesis:

This means that $\mu = 0.16, \sigma = \sqrt{0.16*0.84}$

In a sample of 200 graduates, 24 students have a GPA of 3.00 or below.

This means that $n = 200, X = \frac{24}{200} = 0.12$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.12 - 0.16}{\frac{\sqrt{0.16*0.84}}{\sqrt{200}}}$

$z = -1.54$

Pvalue:

The pvalue is the probability of finding a sample mean above 0.12, which is 1 subtracted by the pvalue of z = -1.54.

Looking at the z-table, z = -1.54 has a pvalue of 0.0618

1 - 0.0618 = 0.9382

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

6 0

3 years ago