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2 years ago

Write this ratio in its simplest form5kg : 20g

Mathematics

2 answers:

posledela2 years ago

5 0

Answer:

1kg:4g

Step-by-step explanation:

nalin [4]2 years ago

3 0

Answer:

1kg : 4kg

Step-by-step explanation:

You need to simplify the current equation

5 : 20

Divide both sides by 5

5/5 : 20/5

1 : 4

1kg : 4kg

Hope this helps!

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Which solid has a greater volume

Triss [41]

Answer:

The volume of cylinder and the volume of a cone, have equal volume measurements. So, the answer is C).

Step-by-step explanation:

Cylinder:

-Use the formula for the volume of a cylinder. Use both the radius and height for the formula in order to solve and get the volume:

$V = \pi r^2 h$

$V = \pi 2^2 6$

-Solve:

$V = \pi 2^2 6$

$V = \pi \times 2^2 \times 6$

$V = \pi \times 4 \times 6$

$V = \pi \times 24$

$V = 24\pi \approx 75.39$

--------------------------------------------------------------------------------------------------------

Cone:

-Use the formula for the volume of a cone and the radius and height for the formula and solve the formula to get the volume:

$V = \frac{1}{3} \pi r^2h$

$V = \frac{1}{3} \pi 3^28$

-Solve:

$V = \frac{1}{3} \pi 3^28$

$V = \frac{1}{3} \times \pi \times 3^2 \times 8$

$V = \frac{1}{3} \times \pi \times 9 \times 8$

$V = \frac{1}{3} \times \pi \times 72$

$V = \frac{1}{3} \pi \times 72$

$V = 24\pi \approx 75.39$

-So, according to the volume of a cylinder and the volume of a cone, They both have the same volume.

Cylinder: $75.39$ $ft^3$

Cone: $75.39$ $ft^3$

5 0

2 years ago

solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+

Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

$\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.$

Write the augmented matrix for the system of equations

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)$

Find the reduced row-echelon form of the augmented matrix for the system of equations:

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)$