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zheka24 [161]
3 years ago
15

Please help !!!!!!!!!

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

Its a i just took the test

Step-by-step explanation:

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Need help ASAP if any can help me that’ll mean a lot I’ll heart your answer :)
Dominik [7]

Answer:

13p+11.75 is no more than 480

Step-by-step explanation:

plz give me brainliest if possible

4 0
3 years ago
...im failing please
Taya2010 [7]

Answer:

top row on 9 page; 9) 53/5 10) 26/4 11) 37/4

bottom row on 9 page; 9) 8 and 1/7 10) 6 and 3/4 11) 1 and 1/3

top row on 3 page; 3) 2 and 2/7 4) 5 and 3/4 5) 8 and 1/10

bottom row on 3 page; 3) 4/3 4) 3/2 5) 12/5

top row on 12 page; 12) 21/10 13) 62/6 14) 57/6

bottom row on 12 page; 12) 1 and 9/10 13) 10 and 1/2 14) 3 and 3/8

Step-by-step explanation:

You never specified if these had to be simplified or turned into a fraction, so I just simplified them. That's about it.

I hope this helps :)

7 0
3 years ago
Plzzzz i will give you brainliest
geniusboy [140]

Answer:

B) 11.8

Step-by-step explanation:

First write in 4 for x and 2 for y

Then multiply 1.3 times 6 (4+2) and subtract 2-6

Your expression should now be 7.8 +4

After adding these, it should be 11.8

5 0
3 years ago
Greg worked 7 hours on Friday and earned an additional $40 in tips. Then he worked 6 hours on Saturday and earned an additional
andre [41]
7d + 40 + 6d + 35 =
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7 0
3 years ago
Read 2 more answers
Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
3 years ago
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