These equations do match up. All you have to do is find the solution to the first equation. After that, plug in that solution to the second equation. If it makes the equation true, then the equations match.
Hope this helps!
<span>3,506,151 that your answer </span>
Answer:
(a)123 km/hr
(b)39 degrees
Step-by-step explanation:
Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.
Distance = Speed X Time
Therefore: PQ =50km/hr X 2 hr =100 km
It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.
Distance, QA=50km/hr X 2.5 hr =125 km
Using alternate angles in the diagram:
(a)First, we calculate the distance traveled, PA by plane Y.
Using Cosine rule
SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am
Time taken =1.5 hour
Therefore:
Average Speed of Y
(b)Flight Direction of Y
Using Law of Sines
The direction of flight Y to the nearest degree is 39 degrees.
Answer:
∠WUV
Step-by-step explanation:
Start from the top, the meeting point of the rays is the angle U
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