Answer:
3.5 hours
Step-by-step explanation:
Speed of train X=30 mph
Speed of train Y=40 mph
Relative speed When the two trains travelling in same direction
Relative speed=40-30=10 mph
Total distance =25+10=35 miles
We have to find the time when train Y is 10 miles ahead of train X.
We know that
Time=
Using the formula
Then, we get
Time=
Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.
For this case we have to:
There are 6 plants per tray.
There are 6 trays for each flat, so for each flat there are 
plants.
Saturday day:
Thus, on Saturday they sold 648 plants.
Sunday: 
Thus, on Saturday they sold 756 plants.
Thus, in total 
plants were sold.
Answer:
plants were sold.
A snack-size bottle of chocolate milk is better because it cost less.
No because (-2, -5) is negative and the y coordinate needs to be positive.
Answer:
I used the function normCdf(lower bound, upper bound, mean, standard deviation) on the graphing calculator to solve this.
- Lower bound = 1914.8
- Upper bound = 999999
- Mean = 1986.1
- Standard deviation = 27.2
Input in these values and it will result in:
normCdf(1914.8,9999999,1986.1,27.2) = 0.995621
So the probability that the value is greater than 1914.8 is about 99.5621%
<u><em>I'm not sure if this is correct </em></u><em>0_o</em>
