Answer and Explanation:
<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee
We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:
1) aa x AA
F1) 4/4=1 Aa
2) Bb x bb
F1) ½ bb
½ Bb
3) dd x Dd
F1) ½ dd
½ Dd
4) Ee x Ee
F1) ¼ EE
2/4 = ½ Ee
¼ ee
So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:
1 Aa x ½ Bb x ½ Dd x ½ Ee = 1/8 AaBbDdEe
Answer:
4
Explanation:
2+2=4. It is a very complex equation. Hope this helps!
-Aslina
Answer:
a. Glycolysis
b. actually, both plants and animals use glycolysis. They use these during cellular respiration and plant respiration
c. Heart tissue!
Explanation:
a. Glycolysis produces 2 ATP per glucose molecule, and thus provides a direct means of producing energy in the absence of oxygen. Lactic acid, the end product of anaerobic glycolysis.
b. In organisms that perform cellular respiration, glycolysis is the first stage of this process. In plants, this metabolic process occurs in the cytosol and plastids of both photosynthetic and non-photosynthetic organs.
c. Pyruvate is an important chemical compound in biochemistry. It is the output of the metabolism of glucose known as glycolysis. In highly oxidative tissue, such as the heart, the production of pyruvate is essential for acetyl-CoA synthesis and L-malate synthesis.
Hope this helps! If you could, please mark this as brainliest :)
<h2>
Answer:</h2><h2>Option C is correct.</h2>
<h2>Explanation: The three components of a nucleotide are a 5-carbon sugar, a phosphate group, and a nitrogenous base. A nucleotide does not contain phospholipids; those are molecules that make up the cell membrane and nuclear envelope.</h2>
