A≈1452.2
A=\pi r^2
R=21.5 because 43/2 is 21.5 so plug and chug
<span>The vertices of are D(7, 3), E(4, -3), and F(10, -3)
Prove tat DE = DF
Length of a segment = </span>√[(x₂ - x₁) +(y₂ -y₁)]
DE = √([4-7)² + (-3 -3)²] = √45 = 3√5
DF = √[(10-7)² +(-3 -3)²] = √45 b= 3√5
Hence DE = DF = 3√5 and DEF is ISOSCELES
Answer:
A. $6.67
Step-by-step explanation:
a) 2y -3x + 8
a) y = - 3/2x + 8/2
a) y = - 3/2x + 4
b) 5y - 15x = -30
b) 5y = 15x - 30
b) y = 15/5x - 30/5
b) y = 3x - 6
3x - 6 = 3/2x + 4
3x -3/2x = 4+6
3/2x = 10
x = (10) / (3/2) = $6.67
Answer:
36.95
Step-by-step explanation:
89- 52.05
=36.95
Answer:
<h3>The 5th term is 30</h3>
Step-by-step explanation:
Given the formula
f(n) = n² + 5
where n is the number of terms
So from the question we were told to find the 5th term that's
n = 5
In order to find the 5th term substitute the value of n that's 5 into the rule
We have
f(5) = 5² + 5
= 25 + 5
= 30
<h3>f(5) = 30</h3>
So the 5th term of the sequence in the given rule is 30
Hope this helps you
