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Harrizon [31]
3 years ago
10

Mark Johnson saves a fixed percentage of his salary at the end of each year. This year he saved $2,500. For each of the next 5 y

ears, he expects his salary to increase at an 10% annual rate, and he plans to increase his savings at the same 10% rate. There will be a total of 6 investments, the initial $2,500 plus five more. If the investments earn a return of 13% per year, how much will Mark have at the end of six years
Business
2 answers:
yarga [219]3 years ago
7 0

Answer:

Mark will have at the end of six years the amount of $25,865.74

Explanation:

According to the given data we have the following:

First investment = 2500

Investment increasing at rate of 10%

Interest rate = 13%

t=6 years

Present value is given by formula = C * [((1+g)^n/(1+i)^n) - 1 ] / (g-i)

C is first value = 2,500

g is increase in investment = 0.10

i is intrest rate = 0.13

n is no of years = 6

Putting values into the equation

P = 2500* [((1+ 0.10)^6/(1+0.13)^6) - 1 ] / (0.10-0.13)  1.771561    2.08195

P = 2500* [((1.10)^6/(1.13)^6) - 1 ] / (-0.03)

P = 2500* [0.8509142870866 - 1 ] / (-0.03)

P = 2500* (-0.14908571)/ (-0.03)

P = 2500* 4.9695236

P=$12,423.809

Future value = P*(1+i)^t

= $12,423.809 *(1+0.13)^6

= $25,865.74

Mark will have at the end of six years the amount of $25,865.74

Artist 52 [7]3 years ago
3 0

Answer:

$29,228.47

Explanation:

year            savings                investment               total

<u>                                                returns                                      </u>

1                  $2,500                (1 + 13%)⁶                  $5,204.88

2                 $2,750                (1 + 13%)⁵                   $5,066.70

3                 $3,025                (1 + 13%)⁴                   $4,932.18

4                 $3,327.50           (1 + 13%)³                   $4,801.24

5                 $3,660.25          (1 + 13%)²                    $4,673.77

<u>6                 $4,026.28           (1 + 13%)                    $4,549.70 </u>

total           $19,289.03                                          $29,228.47

Since Mark earns compound interest, then the returns will be:

  • 1.13⁶ = 2.082
  • 1.13⁵ = 1.8424
  • 1.13⁴ = 1.6305
  • 1.13³ = 1.443
  • 1.13² = 1.2769
  • 1.13¹ = 1.13

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2019: Ending inventory was overstated by $30,000 while depreciation expense was overstated by $24,000. 2020: Ending inventory wa
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Answer:

$25,000

Explanation:

The computation of the adjusted balance of retained earning is shown below:

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3 0
3 years ago
Perdue Company purchased equipment on April 1 for $38,880. The equipment was expected to have a useful life of three years, or 5
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Answer:

See explanation section.

Explanation:

Requirement 1

We know,

Depreciation expense under the straight-line method = (Cost price - residual value) ÷ useful life

The depreciation expense under the straight-line method remains same in every year.

December 31, Year 1 - depreciation expense = ($38,880 - $1,080) ÷ 3 years.

Depreciation expense = ($37,800 ÷ 3)

Depreciation expense = $12,600

Depreciation expense for year 1 = $12,600 × 9 ÷ 12

Depreciation expense for year 1 = $9,450

Requirement 2

The depreciation expense under the straight-line method remains the same every year.

Year 2 depreciation expense = ($38,880 - $1,080) ÷ 3 years = $12,600

Year 3 depreciation expense = ($38,880 - $1,080) ÷ 3 years = $12,600

Year 4 depreciation expense = ($38,880 - $1,080) ÷ 3 years = $12,600

The equipment will be dissolved after 4 year with a residual value of $1,080.

Requirement 3

The depreciation expense under units-of-activity method = [(Cost price - residual value) ÷ Total operating hours] × usage during the period.

Given,

Cost price = $38,880

residual value = $1,080

Total operating hours =  5,400

Putting the values into the formula, we can get

Depreciation expense rate = ($38,880 - $1,080) ÷  5,400

Depreciation expense rate = $37,800 ÷ 5,400

Depreciation expense rate = $7 per hour.

Depreciation expense for year 1 = $7 per hour × 1,000

Depreciation expense for year 1 = $7,000

Requirement 4

We get from requirement 3

Depreciation expense rate = $7 per hour.

Year 2 Depreciation expense = $7 per hour.

Depreciation expense for year 2 = $7 per hour × 1,900 hour.

Depreciation expense for year 2 = $13,300 hour.

Year 3 Depreciation expense = $7 per hour.

Depreciation expense year 3 = $7 per hour ×  1,600 hour.

Depreciation expense year 3 = $11,200 hour.

Year 4 Depreciation expense = $7 per hour.

Depreciation expense year 4 = $7 per hour ×  900 hour.

Depreciation expense year 4 = $6,300 hour.

Requirement 5

Depreciation rate under the double-declining-balance method = (100% ÷ useful life) ÷ 2

Depreciation rate = (100% ÷ 3 years) × 2

Depreciation rate = 66.67%

Depreciation expense for year 1 = cost price × depreciation rate

Given,

cost price = $38,880

depreciation rate = 66.67%

Putting the values into the formula, we can get

Depreciation expense for year 1 = cost price × depreciation rate

Depreciation expense for year 1 = $38,880 × 66.67%

Depreciation expense for year 1 = $25,921

Requirement 6

In double-declining-balance method, depreciation expense is decreasing.

Book value of year 1 after depreciation = Cost price - year 1 depreciation expense =  $38,880 - $25,921 = $12,959

Depreciation expense for year 2 = Book value of year 1 × depreciation rate.

Depreciation expense for year 2 = ($12,959 × 66.67%) = $8,640

Book value of year 2 after depreciation = Book value of year 1 - Depreciation expense for year 2 = $12,959 - $8,640 = $4,319

Depreciation expense for year 3 = Book value of year 2 × depreciation rate.

Depreciation expense for year 3 = $4,319 × 66.67% = $2,879.50

Book value of year 3 after depreciation = Book value of year 2 - Depreciation expense for year 3 = $4,319 - $2,879.50 = $1,439.5

Depreciation expense for year 4 = Book value of year 3 × depreciation rate.

Depreciation expense for year 4 = $1,439.5 × 66.67% = $960

4 0
3 years ago
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