Using the binomial distribution, it is found that the mean of X is of 12, with a standard deviation of 3.36.
For each chip, there are only two possible outcomes, either it is defective, or it is not. The probability of a chip being defective is independent of any other chip, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
Probability of exactly <u>x successes on n repeated trials, with p probability.</u>
The mean of the binomial distribution is:
The standard deviation of the binomial distribution is:
In this problem:
- Six percent of computer chips produced by Cheapo Chips are defective, hence
.
- Each month a random sample of 200 chips manufactured that month are taken, hence
![n = 200](https://tex.z-dn.net/?f=n%20%3D%20200)
Then:
![E(X) = np = 200(0.06) = 12](https://tex.z-dn.net/?f=E%28X%29%20%3D%20np%20%3D%20200%280.06%29%20%3D%2012)
![\sqrt{V(X)} = \sqrt{np(1 - p)} = \sqrt{200(0.06)(0.94)} = 3.36](https://tex.z-dn.net/?f=%5Csqrt%7BV%28X%29%7D%20%3D%20%5Csqrt%7Bnp%281%20-%20p%29%7D%20%3D%20%5Csqrt%7B200%280.06%29%280.94%29%7D%20%3D%203.36)
The mean of X is of 12, with a standard deviation of 3.36.
A similar problem is given at brainly.com/question/12473640
If the equation is
then the domain is the set of all real numbers.
We can replace x with any real number and compute to get some real number output for y. There are no division by zero restrictions to worry about, or issues with taking a square root of a negative number (since this isn't really a square root function).
The cube root of a negative number is negative. For example,
because (-4)^3 = (-4)*(-4)*(-4) = -64.
In interval notation, the domain would be written as
to indicate the entire real number line.
Answer:
x>4/3 and x<1
Step-by-step explanation:
8x-4 < -12
8x<-12+4
x<8/8
x<1
8x+7> 23
8x>23-7
x>12/8
simplify : x>4/3
There were 4 number of treatment conditions compared in this experiment for the given degree of freedom.
We have,
df = 3, 36
Now,
We know that,
Degree of freedom (df) = Number of treatments (t) - 1
i.e.
df = t - 1
So,
We have,
df = 3
Now,
Substituting the values,
We get,
3 = t - 1,
i.e.
t = 4
So, number of treatments conditions = 4
Hence we can say that there were 4 number of treatment conditions compared in this experiment for the given degree of freedom.
Learn more about treatments conditions here
brainly.com/question/23851035
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