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tatyana61 [14]
3 years ago
10

3. Which of the following are the roots of the quadratic function below?

Mathematics
2 answers:
Stels [109]3 years ago
8 0
Answer I don’t know sorry
sergejj [24]3 years ago
4 0

Answer:

x = ± 12

Step-by-step explanation:

Given

f(x) = x² - 144

To find the roots set f(x) = 0, that is

x² - 144 = 0 ( add 144 to both sides )

x² = 144 ( take the square root of both sides )

x = ± \sqrt{144} = ± 12

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Write the number 8.8 x 106 in standard form.
Musya8 [376]

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932.8

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Hope this helps!

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Please help and show work!!! 20+ points!!!!
gregori [183]

Answer:

Red rose is 4/14

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2 years ago
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2. If m 26 = 128°, calculate m25, m_1, and m23.<br> +<br> 5 6<br> 113<br> 42<br> 7 8
rusak2 [61]

Answer:

m∠5= 52°

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m∠3= 52°

Step-by-step explanation:

Please see the attached picture for the full solution.

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7 0
3 years ago
s (as needed, enter in your answers as inf): for the solution through the top-left point: for the solution through the origin: f
antoniya [11.8K]
  1. 3(y->3) is the direction of the top left point's solution.
  2. The answer via origin is often 3(y->3).
  3. The bottom-right point of the solution tends to -infinity.

As x rises, all converge on 3, which is stable.

As x rises, all shift away from -1, making it unstable.

What are equilibrium solutions?

⇒ It is the response to which other responses either move in the opposite direction or tend to approach when t. Because the solution does not depend on time (or any other variable you are integrating over) at those moments, the situation is in equilibrium. Stable solutions are those that "attract" other solutions that started nearby. Stable solutions are those that don't "push away" unstable ones that started nearby. Finally, solutions that, depending on the side from which other solutions started, either attract or push other solutions are referred to as semi-stable solutions. The values of y for which the differential equation states that dy/dt=0 are the equilibrium solutions. Therefore, at those values of y, there are constant solutions.

Calculation:

The equilibrium solutions:

0.7(1+y) (3−y)=0

⇒ y=-1 and y=3 are the equilibrium solutions.

Hence y=-1 and y=3 are the equilibrium solutions.

Learn more about equilibrium solutions here:

brainly.com/question/23885178

#SPJ4

3 0
2 years ago
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