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anyanavicka [17]
3 years ago
14

Choose all the answers that apply.

Computers and Technology
2 answers:
Lapatulllka [165]3 years ago
8 0

the correct answer is location, time of day, time of year and weather,,, EVERY ONE EXCEPT WIND PATTERNS

den301095 [7]3 years ago
7 0
[1] is false, because we are talking about light reaching Earth's surface as a whole, and not in one specific place.

[2] is false, because even if it was in the middle of the night, the other side of the world will be recieving pretty much just as much light as you did the following day.

[3] is false, because even though the sun comes up lower during Winter months, and higher during Summer months, seasons are not constant throughout the entire world. So for what may be Winter for you, will likely be Summer for someone else, so still, just as much light is reaching the Earth.

[4] is false, because wind doesn't affect how light travels.

[5] is true, because clear skies will allow more light to come through that cloudy skies, for example, meaning the amount of light reaching the Earth's surface would not be consistent.
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A _____ system allows a customer to request a fax using email, via the company website, or by telephone.
balu736 [363]

A faxback system allows a customer to request a fax using email, via the company website, or by telephone.

<h3>What is faxback?</h3>

Faxback (usually uncountable, plural faxback) An interactive electronic service permitting documents to be downloaded via fax machine. FaxBack searches a pre-assigned database to validate numerals provided while at the same time recovering a caller's name and fax number. Callers without an account can hear a message in- structing them on how to receive an account or be given the option of furnishing a credit card.

FaxBack Fax Machine Solutions add features to the fax machine equivalent to how VoIP added components to the phone: receive fax notification via email and track, archive, and manage faxes via the fax server or service provider control panel.

Hence, A faxback system allows a customer to request a fax using email, via the company website, or by telephone.

To learn more about faxback refer to:

brainly.com/question/13735750

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4 0
11 months ago
V.kofiryfh givnyovb (to slove you must go back 3 letters)
Elena L [17]
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7 0
3 years ago
If you type too much text on a PowerPoint slide, the additional text is added to a second slide.
Snowcat [4.5K]

Answer:

This is false

The text just goes out of the slide and you can't see it until you lower the font size or until you delete some of it.

Explanation:

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3 years ago
Write a function int checkBalance(char exp[]); that can take an expression as input and check whether the parenthesis used in th
mylen [45]

Answer:

Explanation:

The following code is written in Java. It uses for loops to loop through the array of characters, and uses IF statements to check if the symbols in the expression are balanced. If so it returns true, otherwise it breaks the function and returns false. Two test cases have been provided in the main method and the output can be seen in the attached image below.

import java.util.ArrayList;

class Brainly {

   public static void main(String[] args) {

       char[] exp = { '[', 'A', '*', '{', 'B', '(', 'C', 'D', ')', '}', ']'};

       char[] exp2 = {'[', 'A', '*', '(', 'C', '}', ']'};

       System.out.println(checkBalance(exp));

       System.out.println(checkBalance(exp2));

   }

   public static boolean checkBalance(char exp[]) {

       ArrayList<Character> symbols = new ArrayList<>();

       for (char x: exp) {

           if ((x =='[') || (x == '{') || (x == '(')) {

               symbols.add(x);

           }

           if (x ==']') {

               if (symbols.get(symbols.size()-1) == '[') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

           if (x =='}') {

               if (symbols.get(symbols.size()-1) == '{') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

           if (x ==')') {

               if (symbols.get(symbols.size()-1) == '(') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

       }

       return true;

   }

}

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Answer:

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