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barxatty [35]
3 years ago
6

I need help with my homework

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

more ig

Step-by-step explanation:

y=-5x+20

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Please help and show your work​
BabaBlast [244]
Marcus shoes: 35.99(5.5%)= (about) $1.98(tax) so 35.99+1.98= 37.97

Tia shoes: 39.99(9%)= (about)3.60 (tax) so 39.99+3.60=43.59

However it’s 15% off so 43.59(15%)= 6.54 so 43.59-6.54= 37.05

The difference is 0.92
6 0
4 years ago
Can someone help with this fast
Ray Of Light [21]

Answer:

12. 37. 13. 48 14. 75. For 15-17 just do the two angles equal to each other. for example (5x-17)=(3x-14) and find x. Same with 7 and 8

I'll show you how to do the first one.

4 0
3 years ago
Read 2 more answers
I will mark brainliest! Order the following numbers from least to greatest.
Iteru [2.4K]
5/4, 1.3, 1 8/25 is ur answer
4 0
3 years ago
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Find the maximum rate of change of f at the given point and the direction in which it occurs. f(p, q) = 8qe−p + 4pe−q, (0, 0) ma
Pachacha [2.7K]

Answer:

Step-by-step explanation:

Given \ f (p,q) = 8qe^{-p} + 4pe^{-q}  \  where \ P_o(0,0) \\ \text{thus the gradient of f is: }  \\ \\  \bigtriangledown f(p,q) = \Big(\dfrac{\partial f}{\partial p}, \dfrac{\partial f}{\partial q} \Big) \\ \\  \dfrac{\partial f}{\partial p} = -8qe^{-p} + 4pe^{-q} \\ \\ \dfrac{\partial f}{\partial p} = 8qe^{-p} - 4pe^{-q}  \\ \\  Then: \bigtriangledown f(p.q) = (-4qe^{-p}+ 8qe^{-q}, 4qe^{-p}- 8qe^{-q}) \\ \\ f(0,0) = (-4*(0)e^{-0}+ 8*(0)e^{-(0)}, 4*(0)e^{-(0)}- 8*(0)e^{-(0)})  \\ \\  = (0+8,4-0)  = (8.4)

\Big| \Big | \bigtriangledown f(0,0) = \sqrt{(8)^2+4^2}  \\ \\ = \sqrt{64+16} \\ \\ =  \sqrt{80}

\mathbf{the \ direction \ of \ maximum \ change  \ is }= \mathbf{\sqrt{80}}  \\ \\  \mathbf{direction }(8,4)

7 0
3 years ago
A motorist travels 406 km during a 7 hr period. What was the average speed in km/hr and m/s?
aalyn [17]

Answer:

The answer is:

58 km/hr

16.1 m/s

Step-by-step explanation:

406 km in 7h

x km  in 1h

x= 1 x 406/7

x= 58 km/hr


58 km/hr ⇒⇒⇒⇒⇒⇒ 16.1 m/s

4 0
4 years ago
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