Answer:
a = 22
b = 7
Step-by-step explanation:
Let the two numbers be represented as a and b.
a + b = 29
a - b = 15
Using elimination method
Add both equations
2a = 44
Divide both sides by 2 to get a
2a/2 = 44/2
a = 22
Now substitute a = 22 in any of the equations to get b .
Using the first equation, we have
a + b = 29
22 + b = 29
Subtract 22 from both sides of the equation
22 - 22 + b = 29 - 22
b = 7
Therefore the two numbers are 22 and 7
Answer:
Ham costs: $8.249 repeating
Overall cost: 1.26 repeating
Step-by-step explanation:
$4.95 x 5/3= 8.249
2/3 + 3/5= (2 x 5) + (3 x 3)/ 3 x 5=
19/ 15 or 1 4/15
15 divided by 19= 1.26 repeating
Answer: 0.59 cents per a pounds =y
Step-by-step explanation:I dont know if this is what you are talking about
Answer:
, a linear equation is an equation that may be put in the form where are the variables, and are the coefficients, which are often real numbers. The coefficients may be considered as parameters of the equation, and may be arbitrary expressions, provided they do not contain any of the variables.
Step-by-step explanation:
y= 2x+1 is a linear equation
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
