What is 0.78 reapeating as a simplified fraction
1 answer:
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Answer: Choice B. k(h(g(f(x))))
For choice B, the functions are k, h, g, f going from left to right.
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Explanation:
We have 4x involved, so we'll need f(x)
This 4x term is inside a cubic, so we'll need g(x) as well.
So far we have
g(x) = x^3
g( f(x) ) = ( f(x) )^3
g( f(x) ) = ( 4x )^3
Then note how we are dividing that result by 2. That's the same as applying the h(x) function
And finally, we subtract 1 from this, but that's the same as using k(x)
This leads to the answer choice B.
To be honest, this notation is a mess considering how many function compositions are going on. It's very easy to get lost. I recommend carefully stepping through the problem and building it up in the way I've done above, or in a similar fashion. The idea is to start from the inside and work your way out. Keep in mind that PEMDAS plays a role.
Answer:
1. " second picture"
2. The graph of h(x) is shown below.
Step-by-step explanation:
The given function is
h(x)=7\sin xh(x)=7sinx
The general form of sine function is
f(x)=a\sin(bx+c)+df(x)=asin(bx+c)+d
Where, a is amplitude, b is period, c is phase shift and d is vertical shift.
So, the amplitude of the given function is 7, period is 1, phase shift is 0 and vertical shift is 0.
It means the minimum value of function is -7 and maximum value is 7.
Put x=0 in the given function.
h(x)=7\sin (0)=7(0)=0h(x)=7sin(0)=7(0)=0
Put x=-\frac{\pi}{2}x=− 2ππ in the given function.
h(x)=7\sin (-\frac{\pi}{2})=-7(1)=-7h(x)=7sin(−2π )=−7(1)=−7
Put x=\frac{\pi}{2}x= 2π in the given function.
h(x)=7\sin (\frac{\pi}{2})=7(1)=7h(x)=7sin( 2π )=7(1)=7
Therefore the points on the function are (0,0), (-\frac{\pi}{2},-7),(\frac{\pi}{2},7)(− 2π ,−7),( 2π,7) .
The graph of function is shown below.
"Hope this helps"
