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2 years ago

5

Suppose that during one period extreme cold,the average daily temperature decreased 1 1/2 F each day. How many days did it take

for the temperature to decrease by 9F?

1 answer:

Alenkasestr [34]2 years ago

7 0

We have been given that during one period extreme cold, the average daily temperature decreased $1\frac{1}{2}$ degree F each day. We are asked to find number of days it will take for the temperature to decrease by 9 degree F.

First of all we will convert our mixed fraction into improper fraction.

$1\frac{1}{2}=\frac{3}{2}$

Now we will divide total temperature change (9) by average daily temperature change ( $\frac{3}{2}$ ) to find number of days.

$9\div\frac{3}{2}$

Dividing a number by a fraction is same as multiplying the number by reciprocal of the fraction.

$9\cdot\frac{2}{3}$

$3\cdot2=6$

Therefore, it will take 6 days for the temperature to decrease by 9 degree F.

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9.4 the tangent ratio<br> please help on #27 and 28

Ilya [14]

Answer/Step-by-step explanation:

27.

✔️Sin 23 = opp/hyp

Sin 23 = t/34

34*sin 23 = t

t = 13.3

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Cos 23 = s/34

s = 34*cos 23

s = 31.3

28.

✔️Sin 36 = opp/hyp

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s = 5*sin 36

s = 2.9

✔️Cos 36 = adj/hyp

Cos 36 = r/5

r = 5*cos 36

r = 4.0

29.

✔️Sin 70 = opp/hyp

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✔️Cos 70 = adj/hyp

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6 0

2 years ago

Please help hurry!!!!! This is due in a couple of minutes!!!!

kumpel [21]

Answer:

200 in.

Step-by-step explanation:

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600/3=200 simplification

5 0

3 years ago

Idk this is supper hard

vlabodo [156]

Answer:

The equation of the line is: y = x + 4

Step-by-step explanation:

When we are given two points passing through a line, we can find the equation of the line by using two - point form.

Two - point form: $\frac{\textbf{y - y}_\textbf{1}}{\textbf{y}_{\textbf{2}} \textbf{-} \textbf{y}_{\textbf{1}}} = \frac{{\textbf{x - x}_\textbf{1}}}{\textbf{x}_{\textbf{2}} \textbf{-} \textbf{x}_{\textbf{1}} }$

where $(x_1, y_1) \hspace{3mm} \& \hspace{3mm} (x_2, y_2)$ are the points passing through the line.

Here, let us take two points (can be any two):

$(x _1, y_1) = (1, 5)$ and

$(x_2, y_2) = (5, 9)$

Therefore, we have:

$\frac{y - 5}{9 - 5} = \frac{x - 1}{5 - 1}$

$\iff \frac{y - 5}{4} = \frac{x - 1}{4}$

$\iff y - 5 = x - 1$

$\implies y = x - 1 + 5$

$\implies y = \textbf{x + 4}$ which is the required answer.

4 0

3 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

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3 years ago

How do you write 3.50 x 102 in standard form?

vekshin1

357 is your answer because all you do is solve the problem =

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3 years ago