1. 4g= 37-5
⇒ 4g= 32
⇒ g= 32/4
⇒ g= 8
2. c= 5*6
⇒ c= 30
3. f+4= 3*5
⇒f+4= 15
⇒ f= 15-4
⇒ f= 11.
4. b+6= 30/5
⇒ b+6= 6
⇒ b= 6-6
⇒ b=0
5. a-5= 60/5
⇒ a-5= 12
⇒ a= 12+5
⇒ a= 17
6. e+2= 45/5
⇒ e+2= 9
⇒ e= 9-2
⇒ e= 7
7. d-5= 12/3
⇒ d-5= 4
⇒ d= 4+5
⇒ d= 9
8. m-4= 16/4
⇒ m-4= 4
⇒ m= 4+4
⇒ m= 8
9. q+6= 30/5
⇒ q+6= 6
⇒ q= 6-6
⇒ q= 0
10. h/3= 3+5
⇒ h/3= 8
⇒ h= 8*3
⇒ h= 24
11. 3c= 3-5
⇒ 3c= -2
⇒ c= -2/3
12. x/3= 6-7
⇒ x/3= -1
⇒ x= -1*3
⇒ x= -3
13. 6p= 2+1
⇒ 6p= 3
⇒ p= 3/6
⇒ p= 1/2
14. 2d-7= 27/3
⇒ 2d-7= 9
⇒ 2d= 9+7
⇒ 2d= 16
⇒ d= 16/2
⇒ d=8
15. b-3= 5/2
⇒ b-3= 2.5
⇒ b= 2.5+3
⇒ b= 5.5
16. y-1= 1/3
⇒ y= 1/3+1
⇒ y= 1 1/3
17. 5v= 9-3
⇒ 5v= 6
⇒ v= 6/5
⇒ v= 1.2
18. n-3 = 3*6
⇒ n-3= 18
⇒ n= 18+3
⇒ n= 21
19. t+10= 1*4
⇒ t+10= 4
⇒ t= 4-10
⇒ t= -6
20. 3c+4= 3*5
⇒ 3c+4= 15
⇒ 3c= 15-4
⇒ 3c= 11
⇒ c= 11/3
⇒ c= 3 2/3
Hope this helps~
Okay so the formula is
1. Divide the numerator by the denominator.
2. Write down the whole number answer.
3. Then write down any remainder above the denominator.
so your answer is 2 1/4
Answer:
0.00002 = 0.002% probability of actually having the disease
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Positive test
Event B: Having the disease
Probability of having a positive test:
0.05 of 1 - 0.000001(false positive)
0.99 of 0.000001 positive. So
Probability of a positive test and having the disease:
0.99 of 0.000001. So
What is the probability of actually having the disease
0.00002 = 0.002% probability of actually having the disease
The second answer is correct
Answer:
B
Step-by-step explanation:
Since x is 2 wherever you see x put 2
solve x3 + x7+ 2
=(2)3 + (2)7 + 2
= you do the number outside the bracket multiplied by the number inside the bracket
like this
=(2 × 3) + (2 × 7) + 2
= 6+ 14 + 2
= 22
