Answer:C
Explanation: This has no basis while the others have studied behind them.
Answer:
348 + 395 = 743
Hence, together they have 743 pennies and not 653 pennies. And we cannot perform the rounding, as that is the case when we have the decimal number or the float number. Only then we have the digits after the decimal. And if it's more than 5, we add 1 to the previous or else leave the number as it is. And we go on performing from right to left, and till the number of decimal places, we need to round off. However, here its purely an integer, and hence we cannot round off, as that will result in a significant loss, and which is not acceptable. However, if we want to round off before decimal places as well, then in that case 743 will be $7s, and 653 pennies will be 6+1= $7s, and if this level of loss is acceptable then we can assume that they have the same sum of money. However, here the answer is given in pennies, and hence this is not the case. And hence the answer given in the question is not correct.
Explanation:
The answer is self-explanatory. And since both are numbers, rounding is not required(as explained in the answer section), as it is required in case of decimal and float(as explained in the answer section). And as explained in the answer section, if we can tolerate very heavy loss, then the numbers as well can be rounded off as explained in the answer section. But that is not the case here, as the answer is given in pennies.
Blockchain with cryptocurrency Bitcoin; however, there are many other uses of blockchain; such as Litecoin, Ether, and other currencies. In this discussion, Explanation:
Answer:
A C programming language was used to write a file lorum.txt and counts the number of characters on each line.
Explanation:
Raw_Code :
#include<stdio.h>
int main(){
FILE *read,*write; //creating file pointers
int line=1,count=0;
char ch;
read = fopen("lorum.txt","r"); //opening files to read and write
write = fopen("count.txt","w");
while((ch = getc(read))!=EOF){ //reading lines until end of the file
if(ch == '\n'){ //if new line character encountred
fprintf(write,"%d: %d\n",line,count); //Then printing count of that line to file
line++; //incrementing the count of lines
count = 0; //making characters count to 0
}
else{
count++; //if it is not new line character then increasing character count
}
}
fprintf(write,"%d: %d",line,count); //writing last lines count to count.txt
fclose(read);
fclose(write);
return 0;
}
Answer:
I need help with that too I have that too
Explanation:
